如何分组堆叠条形图，让同组的多个堆叠条共用同一个标签？

思路是将绘图的x轴替换为个体列，保证每个个体对应一根独立的条形，再手动计算每个分组的y轴位置区间，仅在每个分组的居中位置展示一次分组标签，即可消除重复的组标签。

完整可运行代码如下：

import pandas as pd
import matplotlib.pyplot as plt
import numpy as np

# 固定随机种子方便结果复现
np.random.seed(42)
df = pd.DataFrame(
        {'Group':["A","A","B","B","C","C","C","D"],
         'Individual':["ind1","ind2","ind3","ind4","ind5","ind6","ind7","ind8"],
         'Component1':list(np.random.random(8)),
         'Component2':list(np.random.random(8)),
         'Component3':list(np.random.random(8)),
         'Component4':list(np.random.random(8))
        })

# 绘制堆叠水平条形图，x轴指定为Individual保证每个个体对应一根条形
ax = df.plot(x="Individual", y=["Component1","Component2","Component3","Component4"], 
             kind="barh", stacked=True, legend=None, width=1, xlabel="")

# 计算每个分组对应的y轴位置区间
group_pos = df.reset_index().groupby('Group')['index'].agg(['min', 'max'])
# 计算每个分组标签对应的居中展示位置
group_pos['mid'] = (group_pos['min'] + group_pos['max']) / 2

# 替换y轴刻度，仅保留每个分组的单个标签
ax.set_yticks(group_pos['mid'])
ax.set_yticklabels(group_pos.index)

# 可选：添加分组分隔线，让分组边界更清晰，不需要可删除本段代码
for pos in group_pos['max'][:-1]:
    ax.axhline(pos + 0.5, color='gray', linestyle='--', linewidth=0.8)

plt.tight_layout()
plt.show()

内容的提问来源于stack exchange，提问作者dasilvan9