Python调用station类stat_info方法返回函数对象而非站点列表问题解决

• 代码中station.stat_info是直接引用类的方法对象，没有执行调用（缺少()），同时也没有针对你创建的przystanki站点实例列表操作，无法得到所有站点的名称集合。
• 你定义的stat_info方法是单个站点实例的方法，返回的是当前站点自己的名称列表，不能直接返回所有站点的名称。

class station:
    def __init__(self, name, possibility_of_change, time_of_stay):
        self.name = name
        self.possibility_of_change = possibility_of_change
        self.time_of_stay = time_of_stay
        stat = []
        stat.append(self.name)
        self.stat = stat

    def stat_info(self):
        return self.stat


class Position_of_route:
    def __init__(self, station, time_between_2_stays):
        self.station = station
        self.time_between_2_stays = time_between_2_stays


class Route(station):
    def __init__(self, name1, list_of_positions):
        self.name1 = name1
        self.list_of_postitions = list_of_positions
    
    def trasa_info(self):
        return 5


    def generate(self, time):
        przystanki = [
            station("Warszawa1",True,3),
            station("Warszawa2",True,5),
            station("Warszawa3",False,0),
            station("Warszawa4",True,3),
            station("Warszawa5",True,7),
            station("Warszawa6",True,3),
            station("Warszawa7",True,9),
            station("Warszawa8",False,0),
            station("Warszawa9",True,12),
        ]
        # 遍历所有站点实例，调用stat_info方法收集所有站点名称
        station_names = [st.stat_info()[0] for st in przystanki]
        a={
            "Name and information": [self.name1, station_names]
        }
        return a
        
print(Route("Ko",[1,2]).generate(18))

{'Name and information': ['Ko', ['Warszawa1', 'Warszawa2', 'Warszawa3', 'Warszawa4', 'Warszawa5', 'Warszawa6', 'Warszawa7', 'Warszawa8', 'Warszawa9']]}

如果你不需要复用stat_info方法，也可以直接取实例的name属性，收集列表的写法改为station_names = [st.name for st in przystanki]，效果完全一致。

内容的提问来源于stack exchange，提问作者Kokin