Python中if语句后是否必须加else 不改动现有Yahtzee骰子程序

Python语法不强制要求if语句必须搭配else分支，你当前的代码不需要做任何修改就能正常运行，完全不会影响现有逻辑。

• if分支的本质是「仅当条件成立时，执行块内代码」，条件不成立时解释器会直接跳过整个if块，继续执行后续代码，不会出现语法报错。
• 只有当你需要明确处理「条件不成立」的场景时，才有必要添加else分支。比如你想在没掷出三个相同点数时打印No match提示，才需要补else块；按照你现在的需求——只在匹配成功时计数、打匹配标记，非匹配场景不需要额外操作，只写if就是最简洁正确的写法，强行加else反而冗余。

#Program 2#
#create a Yatzhee dice program#
import random

print("--------------------")
print("Yatzhee dice program")
print("--------------------")
print("")
print("Welcome to the Yatzhee Dice Program")
print("In this program the dice will get rolled 50 times and at the end we tell you how many matches you got.")
print("")
# before loop #

rolls = 50
total_matches = 0

# --- loop ---

for i in range(rolls): #randomise 50 times#
    die1 = random.randint(1, 6)
    die2 = random.randint(1, 6)#chooses a number from 1 to 6#
    die3 = random.randint(1, 6)

    print(die1, "|", die2, "|", die3)

    if die1 == die2 == die3:#If all three are the same.#
        print("****MATCH*****")#If statement inside for-loop so it adds up how many matches there were#
        total_matches += 1 #increases no. of matches by 1 each time there is a match#

#after loop#

print("")
print("The total number of matches was:", total_matches)#tells user how many matches there were#

小备注：常规Yahtzee规则使用5枚骰子，你当前用3枚属于自定义规则，只要符合你的设计预期就不需要调整。

内容的提问来源于stack exchange，提问作者Harry