使用Sympy求解函数公切点二元微分方程仅得平凡解的问题排查
双势阱函数公切点求解问题
问题描述
现有名为F的双势阱函数,函数形态可参考双势阱曲线示例。需要在给定区间内求解函数的两个公切点(x1,F(x1))、(x2,F(x2)),对应约束方程为:
F'(x1)=F'(x2) (1) F'(x1)*(x2-x1)+F(x1)=F(x2) (2)
代码实现与异常
使用sympy.solve编写求解代码如下:
x1 = Symbol('x1') F1 = F(x1,AA, BB, CC, DD, EE, FF) x2 = Symbol('x2') F2 = F(x2,AA, BB, CC, DD, EE, FF) dF1=diff(F1,x1) dF2=diff(F2,x2) print(solve([dF1-dF2, F2-F1-dF1*(x2-x1)], [x1, x2]))
代码运行输出为[(x2, x2)],仅返回x1=x2的平凡解,无有效非平凡解输出。
待解决疑问
- 求解时如何设置
x1 != x2的约束,排除无效平凡解? - 如何获取上述方程的数值求解结果?
- 如何将
x1和x2的解限制在指定区间范围内?
正确性验证
测试其他求解逻辑均可得到正确结果,测试代码如下:
print(solve([y1+y2,y1-y2], [x1, x2])) print(solve(dy1, x1))
打印各中间表达式确认正确性,执行输出如下:
------------------------------------------------------------------- In [1]: x1 = Symbol('x1') F1 = F(x1,AA, BB, CC, DD, EE, FF) x2 = Symbol('x2') F2 = F(x2,AA, BB, CC, DD, EE, FF) dF1=diff(F1,x1) dF2=diff(F2,x2) ------------------------------------------------------------------- In [2]: F1 Out[2]: 𝑥1⋅(1−𝑥1)(−0.0501765666583873𝑥1+0.244249682150038(2𝑥1−1)5−0.535363152864316(2𝑥1−1)4+0.197479965493092(2𝑥1−1)3−0.366799918223659(2𝑥1−1)2−0.203076238788926) (Out [2] 为函数F的正确表达式) ------------------------------------------------------------------- In [3]:dF1 Out[3]:𝑥1⋅(1−𝑥1)(−2.93439934578927𝑥1+2.44249682150038(2𝑥1−1)4−4.28290522291453(2𝑥1−1)3+1.18487979295855(2𝑥1−1)2+1.41702310623625)−𝑥1(−0.0501765666583873𝑥1+0.244249682150038(2𝑥1−1)5−0.535363152864316(2𝑥1−1)4+0.197479965493092(2𝑥1−1)3−0.366799918223659(2𝑥1−1)2−0.203076238788926)+(1−𝑥1)(−0.0501765666583873𝑥1+0.244249682150038(2𝑥1−1)5−0.535363152864316(2𝑥1−1)4+0.197479965493092(2𝑥1−1)3−0.366799918223659(2𝑥1−1)2−0.203076238788926) (Out [3] 为F的导函数,表达式正确) ------------------------------------------------------------------- In [4]:print(solve([F1+F2,F1-F2], [x1, x2])) [(0.0, 0.0), (0.0, 1.00000000000000), (1.00000000000000, 0.0), (1.00000000000000, 1.00000000000000)] (In [4] 求解结果正确) ------------------------------------------------------------------- In [5]:print(solve(dF1, x1)) [0.143449671600321, 0.462174698289538, 0.744534434388284, 1.44258261390104, 0.573315370351492 - 0.261496971434863*I, 0.573315370351492 + 0.261496971434863*I] (In [5] 单变量导函数求根结果正确) ------------------------------------------------------------------- In [6]:print(solve([dF1-dF2, F2-F1-dF1*(x2-x1)], [x1, x2])) [(x2, x2)] (In [6] 为目标方程求解结果,仅返回平凡解,是核心问题) -------------------------------------------------------------------
内容的提问来源于stack exchange,提问作者Er g Ch
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