Python中如何将多对象组合为单个元素追加至列表？append报错

嘿，我懂你的困扰啦！你遇到的TypeError: append() takes exactly one argument (3 given)错误，原因很直接——Python的list.append()方法只能接收一个参数，你一次性传了三个字符串（牌面、"of"、花色），它自然就懵啦。

要实现你想要的「把三个部分组合成类似"Two of Hearts"的单个元素加到列表末尾」的需求，有几种简单的解决办法：

方法1：用f-string拼接成完整字符串（最推荐） #

f-string是Python 3.6+最简洁直观的字符串拼接方式，先把三个部分拼成一个完整的字符串，再传给append()：

import random  # 别忘了导入random模块，不然randint用不了哦
yourCards = []
cards =["Ace","Two","Three","Four","Five","Six","Seven","Eight","Nine","Ten","Jack","Queen","King"]
suits = ["Hearts","Diamonds","Clubs","Spades"]

# 拼接成目标格式的字符串，再添加到列表
yourCards.append(f"{cards[random.randint(0,12)]} of {suits[random.randint(0,3)]}")

方法2：用字符串join方法拼接 #

如果习惯用join，也可以把三个元素放到列表里，再用空格连接起来：

import random
yourCards = []
cards =["Ace","Two","Three","Four","Five","Six","Seven","Eight","Nine","Ten","Jack","Queen","King"]
suits = ["Hearts","Diamonds","Clubs","Spades"]

card_element = ' '.join([cards[random.randint(0,12)], "of", suits[random.randint(0,3)]])
yourCards.append(card_element)

方法3：直接在append里拼接（更紧凑） #

要是不想用临时变量，也可以直接在append()的参数里完成拼接：

import random
yourCards = []
cards =["Ace","Two","Three","Four","Five","Six","Seven","Eight","Nine","Ten","Jack","Queen","King"]
suits = ["Hearts","Diamonds","Clubs","Spades"]

yourCards.append(cards[random.randint(0,12)] + " of " + suits[random.randint(0,3)])

这样操作后，yourCards列表末尾就会新增一个类似"Two of Hearts"的完整字符串元素啦～

内容的提问来源于stack exchange，提问作者David Latimer