Python循环中为唯一ID添加校验位并存储的问题求助（含报错）

Hey there! Let's break down what's going wrong and fix your code step by step.

The Root Cause of the Error #

Your Unique variable is an integer (like 101, 102), and you're trying to access its digits using subscript notation (Unique[0])—but integers don't support that! That's exactly why you're getting the 'int' object is not subscriptable error. To get individual digits, you first need to convert the integer to a string.

Corrected Code with Explanations #

Here's the fixed version of your code, with comments explaining each key change:

Staff = []
ID = []
Unique = 100  # Starting base ID number

# Change range(0,3) to range(0,10) if you want 10 names instead of 3
for _ in range(0, 3):
    Name = input("Enter your name:\n")
    Staff.append(Name)
    Unique += 1  # Increment to get the next unique ID
    
    # Convert integer ID to string to access individual digits
    unique_str = str(Unique)
    
    # Extract each digit, convert back to int for calculation
    p1 = int(unique_str[0])
    p2 = int(unique_str[1])
    p3 = int(unique_str[2])
    
    # Calculate the check digit using your weighted sum + MOD 10 logic
    check_digit = ((p1 * 3) + (p2 * 2) + (p3 * 1)) % 10
    
    # Create a full ID (either as a concatenated string or keep as a tuple)
    # Option 1: Concatenated string (more user-friendly for display)
    full_id = f"{Unique}{check_digit}"
    # Option 2: Keep as tuple (matches your original code's structure)
    # full_id = (Unique, check_digit)
    
    ID.append(full_id)

# Print results neatly
for name, staff_id in zip(Staff, ID):
    print(f"Name: {name}, Full ID: {staff_id}")

Key Changes Made #

• Converted Unique to string: This lets us safely access each digit with subscripts (e.g., unique_str[0] gets the first digit of the ID).
• Adjusted check digit calculation: We convert each extracted string digit back to an integer so we can do arithmetic operations on them.
• Improved output formatting: Used zip() to loop through names and IDs together, making the code cleaner than using index-based loops.
• Optional ID format: You can choose between a concatenated string (like 1013) or keep the tuple format ((101, 3)) based on your needs.

Testing the Code #

When you run this, you'll be prompted to enter 3 names (change to 10 by updating the range value). For example, if you enter "Alice" as the first name:

• Unique becomes 101
• Digits are 1, 0, 1
• Weighted sum: (13)+(02)+(1*1) = 4
• Check digit: 4 % 10 = 4
• Full ID becomes 1014

内容的提问来源于stack exchange，提问作者Mr mac