Python调用函数后判断返回值为True展示列表问题排查

核心是代码存在3处明确错误，直接导致预期逻辑不生效：

• （直接引发列表不展示的核心错误）login()函数未返回验证结果。当前代码调用authentication()拿到验证状态后，没有通过return把结果传出，Python中未显式写return语句的函数默认返回None，外层if login():的判断永远不成立，后续遍历打印员工、薪资列表的代码完全不会执行。
• 注册逻辑存在拼写错误：new_login()函数判断输入姓名是否在员工列表时，误把列表名list_employees写为list_employee（少了末尾的s），运行时会直接触发NameError；且原逻辑下如果输入姓名不在员工列表，打印提示后不会中断流程，仍会继续执行后续注册步骤。
• 新增员工逻辑存在语法错误：create_employee()中输入薪资的代码input('Type the employee's salary: ')外层用单引号包裹字符串，字符串内部employee's的单引号会提前截断字符串，运行时直接报语法错误。

list_login = []
list_password = []
list_employees = ['Pedro' , 'Ana', 'Carlos', 'Maria Clara', 'João Antônio']
list_salaries = [3470.00, 2200.00, 3970.34, 7450.23, 5677.33]

def check(login_user):
    return login_user in list_login


def authentication(index,user_password):
    if list_password[index] == user_password:
        print('User authenticated!')
        return True
    else:
        print('Incorrect Password!')
        return False

    
def login():
    login_user = input('Type your login: ')
    user_password = input('Type your password: ')
    if check(login_user):
        index = list_login.index(login_user)
        # 修复：返回认证结果给外层判断
        return authentication(index,user_password)
    else:
        print("Login information is incorrect or does not exist.")
        # 修复：登录失败明确返回False
        return False
        

def new_login():
    name = input('Type your name: ')
    # 修复：修正列表名拼写，输入不合法时直接中断流程
    if name not in list_employees:
        print('Name is not in the emplyee list, type again!')
        return

    login_user = input('Type the login you wish to register: ')
    if login_user in list_login:
        print('There is already a user registered with this login')
        return
    print('Login is available!')
    password_user = input('Type the password that will be registered: ')
    list_login.append(login_user)
    list_password.append(password_user)
    print('User registered!')
    print('Employee name: ', name)
    print('Login saved: ', login_user)
    print('Password saved: ', password_user)


def create_employee():
    name = input('Type the name of the new employee: ')
    # 修复：单引号冲突，改用双引号包裹外层字符串
    salary = float(input("Type the employee's salary: "))
    list_employees.append(name)
    list_salaries.append(salary)
    print('Employee ',name,' registered with the current salary of: ',salary)


while True:
    choice = input(
    '''
    
    MENU
    1- Create Login and Password
    2- Increase salary 10%
    3- Report
    4- Create New Employee
    Choose a option: '''
    )

    if choice == '1':
        new_login()
        
    if choice == '2':
        login()
    
    if choice == '3':
        if login():
            for i in range(len(list_employees)):
                print(list_employees[i],' - ',list_salaries[i])

    if choice == '4':
        create_employee()

内容的提问来源于stack exchange，提问作者Deivid Kutter