Notepad++文本处理需求：将末尾字母移至开头

架构老林

2026-5-11

Got it, let's solve this problem for you! You need to take strings that start with numbers and end with 1-2 letters, then move those trailing letters to the front. Here are a couple of straightforward, practical ways to get this done:

Python Script Solution

If you prefer a reusable script that works across operating systems, this Python approach will let you process your text file easily:

import re

# Regex pattern to capture digits (first group) and trailing 1-2 letters (second group)
pattern = re.compile(r'(\d+)([A-Za-z]{1,2})$')

# Read input file, process each line, then write output
with open('input.txt', 'r') as infile, open('output.txt', 'w') as outfile:
    for line in infile:
        # Split line into individual elements
        elements = line.strip().split()
        processed = []
        for elem in elements:
            match = pattern.match(elem)
            if match:
                # Swap letters and digits
                processed.append(f"{match.group(2)}{match.group(1)}")
            else:
                # Keep elements that don't match the pattern unchanged
                processed.append(elem)
        # Write the processed line back
        outfile.write(' '.join(processed) + '\n')

How it works:

The regex (\d+)([A-Za-z]{1,2})$ targets exactly what you need: one or more digits, followed by 1-2 letters at the end of the string.
For each matching element, we swap the captured letters and digits, then reassemble the line.

Terminal (sed) Solution

If you're on Linux/macOS and want a quick command-line fix, use sed with regex substitution:

sed -E 's/([0-9]+)([A-Za-z]{1,2})/\2\1/g' input.txt > output.txt

How it works:

The s/old/new/g syntax tells sed to replace all matches in each line.
([0-9]+) captures the leading digits, ([A-Za-z]{1,2}) captures the trailing letters.
\2\1 swaps the order of the two captured groups, putting letters first.