如何编写XPath获取XML中指定h4标题后的列表项内容？

Your initial XPath didn't work because the <ul> is a sibling of the <h4>, not a child. The <h4> and <ul> are both nested inside the same parent <div>, so we need to traverse to the following sibling <ul> instead of looking for a direct child.

Here are the precise, position-agnostic XPath expressions for each heading:

• Source: //h4[normalize-space(text())="Source"]/following-sibling::ul[1]/li/text()

  • normalize-space(text()) handles accidental whitespace in the h4 text (like leading/trailing spaces)
  • following-sibling::ul[1] targets the very first <ul> immediately after the matching <h4>, ensuring we grab the correct associated list even if other elements are nearby

• Language: //h4[normalize-space(text())="Language"]/following-sibling::ul[1]/li/text()

  • This captures the text inside the <a> tag (e.g., "Swedish" in your example) because text() retrieves all text nodes within the <li>

• Publishers: //h4[normalize-space(text())="Publishers"]/following-sibling::ul[1]/li/text()

• Record ID: //h4[normalize-space(text())="Record ID"]/following-sibling::ul[1]/li/text()

Bonus: Capture full text content (even with mixed elements) #

If you want to ensure you get all text inside the <li> (including text nested in child elements), use the string() function:
string(//h4[normalize-space(text())="Source"]/following-sibling::ul[1]/li)
This returns the concatenated text content of the node, regardless of any nested tags.

内容的提问来源于stack exchange，提问作者Novienta