Python报TypeError: bad operand type for unary +: 'str'如何解决

报错TypeError: bad operand type for unary +: 'str'的触发点是print语句的语法错误：你在逗号后多写了一个+，Python会把这个和前面值用逗号隔开的+识别为一元正号运算符（类似数字前的正负标记），但一元正号仅支持数字类型操作，你后面跟的是random.choice()返回的字符串类型，直接触发类型错误。
另外代码还存在两个隐含问题：

• 没有导入random模块，修好上述语法错误后运行也会触发NameError
• 当前写法random.choice(harfler) * kackarakter是把同一个随机选中的字母重复N次，如果需求是生成N位随机字母串（多个随机字母组合），现有逻辑不符合预期。

1. 代码开头先导入random模块
2. 删掉print参数里多余的逗号，让+作为字符串拼接运算符使用，而非独立的一元运算符
3. 如果需要生成多字符随机串，替换单字符重复的写法为随机多选后拼接的逻辑

如果需求是输出固定前缀+单个随机字母重复N次：

import random
harfler = ["a","b","c","d","e","f","g","h","i","j","k","l","m","n","o","v","y","z","q","w","x"]
kackarakter = int(input("How Many Letters Do You Want ?:"))
print('("My WordPress Blog")' + random.choice(harfler) * kackarakter)

如果需求是输出固定前缀+N位随机抽取的字母串：

import random
harfler = ["a","b","c","d","e","f","g","h","i","j","k","l","m","n","o","v","y","z","q","w","x"]
kackarakter = int(input("How Many Letters Do You Want ?:"))
random_str = ''.join(random.choices(harfler, k=kackarakter))
print('("My WordPress Blog")' + random_str)

• print函数里用逗号分隔的内容会被识别为多个独立传参，参数之间默认用空格拼接输出，不要在逗号后随意写运算符，否则运算符会单独作用在单个参数上触发意料之外的错误
• 字符串的*运算规则是"a"*3得到"aaa"，是重复单字符串的效果，要生成多随机字符组合需要用random.choices批量选取后拼接。

内容的提问来源于stack exchange，提问作者MuhammedTr768