Python字母电话号码转纯数字代码输出异常问题求助

你的条件判断写法存在语法逻辑错误，这是导致字母映射不全的根本原因：
Python中"A" or "B" or "C"这类表达式不会实现「匹配三个值中任意一个」的效果，or属于短路逻辑运算符，会返回运算中第一个为真的值，非空字符串永远为真，所以这个表达式的计算结果永远是每组的第一个字符：

• "A" or "B" or "C" 结果永远是"A"
• "D" or "E" or "F" 结果永远是"D"
• "G" or "H" or "I" 结果永远是"G"
• 其余分组同理，仅每组第一个字母能进入对应数字映射分支，同组其他字母全部匹配失败，直接走else分支保留原始字符，和你遇到的异常现象完全吻合：
  • 输入1800FLOWERS时，仅W是WXYZ分组的首字符，被转为9，其余F/L/O/E/R/S都不是对应分组首字符，原样保留，输出1800FLO9ERS
  • 输入1800GOTJUNK时，G（GHI首字符）转4、T（TUV首字符）转8、J（JKL首字符）转5，其余字母原样保留，输出18004O85UNK
  • 输入1800BIGFISH时，仅G（GHI首字符）转4，其余字母原样保留，输出1800BI4FISH

把所有等值判断改为成员判断，用in关键字判断字符是否属于对应字母元组即可，修复后完整代码如下：

phonenumber = input("Please input the number you would like to translate, starting with 1800 now, no hyphens:")

def FindNumber(phonenumber):
    number = ""
    for char in phonenumber:
        if char in ("A", "B", "C"):
            number = number + "2"
        elif char in ("D", "E", "F"):
            number = number + "3"
        elif char in ("G", "H", "I"):
            number = number + "4"
        elif char in ("J", "K", "L"):
            number = number + "5"
        elif char in ("M", "N", "O"):
            number = number + "6"
        elif char in ("P", "Q", "R", "S"):
            number = number + "7"
        elif char in ("T", "U", "V"):
            number = number + "8"
        elif char in ("W", "X", "Y", "Z"):
            number = number + "9"
        else:
            number = number + char
    return number
   
print("The number you want to call is", FindNumber(phonenumber))

测试验证：

• 输入1800FLOWERS输出18003569377
• 输入1800GOTJUNK输出18004685865
• 输入1800BIGFISH输出18002443474
  转换结果完全符合预期。

内容的提问来源于stack exchange，提问作者Codapt