如何在R语言数据框中按特定模式合并语音时长数据
Solution for Merging Word Durations in Your DataFrame
Got it, let's work through this problem step by step. You need to merge durations when "n't" follows vowel-ending words like "do" or "ca", while leaving consonant-ending pairs (like "did n't") untouched. Here's a straightforward approach using R:
Step 1: Define a Row Processing Function
First, we'll create a function to handle each row individually. This lets us check for "n't" occurrences, validate the preceding word, and merge durations/words as needed:
process_row <- function(row) { # Extract duration and word columns from the row dur_cols <- paste0("d", 1:10) word_cols <- paste0("w", 1:10) durations <- row[dur_cols] words <- row[word_cols] # Find all positions where the word is "n't" nt_positions <- which(words == "n't") # Iterate backwards to avoid position shifts messing up later checks for (pos in rev(nt_positions)) { if (pos > 1) { prev_word <- words[pos - 1] # Check if preceding word is "do" or "ca" (vowel-ending targets) if (prev_word %in% c("do", "ca")) { # Merge the two words into a single contraction words[pos - 1] <- paste0(prev_word, "n't") # Sum their durations durations[pos - 1] <- durations[pos - 1] + durations[pos] # Remove the standalone "n't" column, shift remaining columns left words <- words[-pos] durations <- durations[-pos] # Fill empty spots with NA to keep 10 columns total if (length(words) < 10) { words <- c(words, rep(NA, 10 - length(words))) } if (length(durations) < 10) { durations <- c(durations, rep(NA, 10 - length(durations))) } } } } # Reconstruct the processed row with original column names new_row <- c(durations, words) names(new_row) <- c(dur_cols, word_cols) return(new_row) }
Step 2: Apply the Function to Your DataFrame
Now we'll use apply() to run this function on every row of test1, then convert the result back to a dataframe:
# Process all rows test_processed <- as.data.frame(t(apply(test1, 1, process_row))) # Restore original row names rownames(test_processed) <- rownames(test1) # Ensure duration columns are numeric (they get coerced to character during transpose) test_processed[, paste0("d", 1:10)] <- lapply(test_processed[, paste0("d", 1:10)], as.numeric)
Step 3: Check the Results
If you print test_processed, you'll see exactly what you're looking for:
- Row 10: "do" and "n't" become "don't" with a merged duration of
0.064 + 0.075 = 0.139 - Row 132: "ca" and "n't" become "can't" with a merged duration of
0.087 + 0.088 = 0.175 - Row 784: "did n't" pairs stay separate since "did" ends with a consonant
Key Notes
- We iterate backwards through "n't" positions so that shifting columns left doesn't break the position indices for remaining checks.
- The function keeps the dataframe structure (10 duration + 10 word columns) by filling empty spots with NA after merging.
- This approach handles multiple "n't" occurrences in a single row automatically.
内容的提问来源于stack exchange,提问作者Chris Ruehlemann
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