如何在Flutter Android的local.properties中设置compileSdkVersion？

可以在local.properties中配置compileSdkVersion，你遇到的报错是因为从配置文件读取到的是字符串类型，而gradle的compileSdkVersion需要整数类型，直接赋值会导致解析错误。

解决步骤： #

1. 保持local.properties的配置不变：

flutter.compileSdkVersion=33

2. 修改app模块下的build.gradle代码，将读取到的字符串转换为整数：

// 读取配置并处理类型转换
def flutterCompileSdkVersion = localProperties.getProperty('flutter.compileSdkVersion')
if (flutterCompileSdkVersion == null) {
    flutterCompileSdkVersion = flutter.compileSdkVersion
} else {
    flutterCompileSdkVersion = flutterCompileSdkVersion.toInteger()
}

// 正常设置compileSdkVersion
compileSdkVersion flutterCompileSdkVersion

或者用更简洁的空安全写法：

def flutterCompileSdkVersion = localProperties.getProperty('flutter.compileSdkVersion')?.toInteger() ?: flutter.compileSdkVersion
compileSdkVersion flutterCompileSdkVersion

报错原因说明： #

你之前的代码直接将字符串类型的配置值传给compileSdkVersion，gradle在处理该参数时会尝试解析整数，字符串类型的输入触发了内部解析逻辑的索引越界错误，转换为整数后即可正常识别。

内容的提问来源于stack exchange，提问作者vietstone