如何使用通用正则表达式将文本中的上标数字替换为普通数字？

Got it! Your current approach works for ² and ³, but to handle all superscript digits (0-9) in one clean step, you can use a regex that matches every superscript digit character paired with a replacement map. Here's how to do it:

Step 1: Create a mapping of superscript digits to regular digits #

First, define an object that maps each superscript character to its corresponding regular digit. This covers all common superscript digits you'll encounter:

const superscriptToRegular = {
  '⁰': '0',
  '¹': '1',
  '²': '2',
  '³': '3',
  '⁴': '4',
  '⁵': '5',
  '⁶': '6',
  '⁷': '7',
  '⁸': '8',
  '⁹': '9'
};

Step 2: Use a single regex replace with a callback function #

Instead of chaining multiple replace() calls, use a regex that matches any of the superscript digits (using a character set [⁰¹²³⁴⁵⁶⁷⁸⁹]) and the g flag to replace all occurrences. The callback function looks up each matched character in our map and returns the regular digit:

const originalText = "V is 100 m³, square is 12 m², 7⁴ equals 2401, and 10⁰ is 1";
const convertedText = originalText.replace(/[⁰¹²³⁴⁵⁶⁷⁸⁹]/g, match => superscriptToRegular[match]);

console.log(convertedText);
// Output: "V is 100 m3, square is 12 m2, 74 equals 2401, and 100 is 1"

Quick typo note #

Your original code has a small typo (repalce instead of replace)—just something to watch out for!

Why this works better #

• Covers all digits: No need to add a new replace() call for every superscript digit you find.
• Easy to extend: If you ever need to handle other superscript characters (like fractions or symbols), you can just add them to the mapping object.
• Clean and maintainable: One single replacement step makes your code easier to read and update.

内容的提问来源于stack exchange，提问作者Erik