如何用Python编写接收字典列表并返回字符串列表的函数

一、修正你的循环实现 #

你的现有代码仅打印了字典的值列表，未处理目标字符串格式，也没有收集结果返回。以下是修正后的代码：

def extract_names(name_list):
    full_names = []
    for person in name_list:
        # 提取名和姓，将姓的首字母大写
        first_name = person['first']
        last_name = person['last'].capitalize()
        full_names.append(f"{first_name} {last_name}")
    return full_names

# 测试示例
name = [{"first":"john","last":"doe"},{"first":"jane","last":"doe"}]
print(extract_names(name))  # 输出: ['john Doe', 'jane Doe']

二、用map函数实现 #

map函数可将处理逻辑批量应用到列表的每个元素上，配合lambda表达式能进一步简化代码：

方式1：单独定义处理函数 #

def format_full_name(person):
    return f"{person['first']} {person['last'].capitalize()}"

def extract_names(name_list):
    # 将map对象转为列表返回
    return list(map(format_full_name, name_list))

# 测试示例
name = [{"first":"john","last":"doe"},{"first":"jane","last":"doe"}]
print(extract_names(name))  # 输出: ['john Doe', 'jane Doe']

方式2：使用lambda简化 #

def extract_names(name_list):
    return list(map(lambda p: f"{p['first']} {p['last'].capitalize()}", name_list))

# 测试示例
name = [{"first":"john","last":"doe"},{"first":"jane","last":"doe"}]
print(extract_names(name))  # 输出: ['john Doe', 'jane Doe']

内容的提问来源于stack exchange，提问作者Karizkhan