关于deep-anpr项目detect.py中f.files的含义及报错问题咨询

Hey there! Let's unpack your question and fix that error right away.

What was f.files supposed to do? #

When you use np.load() on a .npz file (like your weights.npz), the returned object (f here) is an NpzFile—a dictionary-like container holding all the arrays stored in the compressed file.

In older versions of NumPy, this NpzFile object had a .files attribute: it was a list of strings representing the names of all the arrays inside the .npz file. The line of code you're looking at:

param_vals = [f[n] for n in sorted(f.files, key=lambda s: int(s[4:]))]

was designed to:

1. Fetch all array names from the weights file
2. Sort those names by the numeric suffix (since the names are likely formatted like arr_0, arr_1, etc.—s[4:] grabs everything after "arr_", then converts it to an integer for proper numeric sorting)
3. Load each array in that sorted order into the param_vals list

Why are you getting the "no .files method" error? #

Newer versions of NumPy (starting around v1.21.0) removed the .files attribute from NpzFile objects. They replaced it with the .keys() method, which serves exactly the same purpose—returning the list of array names in the file.

How to fix the error #

Simply replace f.files with f.keys() in that line of code. Your corrected line should look like this:

param_vals = [f[n] for n in sorted(f.keys(), key=lambda s: int(s[4:]))]

You can double-check this by running a quick test: print out list(f.keys()) after loading the .npz file. You should see a list of names like ['arr_0', 'arr_1', ...], which confirms the sorting logic will still work as intended.

内容的提问来源于stack exchange，提问作者codcod55