如何从JSON数组中根据operation_name获取对应的operation_id值

首先修正你给出的JSON为标准格式（键和字符串需加双引号）：

[
  {
    "operation_id": 2,
    "operation_name": "FAITHFUL BELIEVERS"
  },
  {
    "operation_id": 3,
    "operation_name": "SAMPLE OP"
  },
  {
    "operation_id": 4,
    "operation_name": "SAMPLE OP 2"
  }
]

下面是两种常用编程语言的实现方式：

JavaScript 实现 #

用数组的find()方法直接定位目标对象，再提取operation_id：

// 解析后的JS对象数组（如果原始是JSON字符串，先用JSON.parse()转换）
const operations = [
  {operation_id: 2, operation_name: "FAITHFUL BELIEVERS"},
  {operation_id: 3, operation_name: "SAMPLE OP"},
  {operation_id: 4, operation_name: "SAMPLE OP 2"}
];

// 查找operation_name为'SAMPLE OP'的对象
const targetOp = operations.find(op => op.operation_name === 'SAMPLE OP');

// 输出结果，找不到时给出提示
if (targetOp) {
  console.log(targetOp.operation_id); // 控制台输出3
} else {
  console.log("没找到匹配的operation_name");
}

Python 实现 #

可以用循环遍历或者生成器表达式快速筛选：

循环遍历方式 #

operations = [
    {"operation_id": 2, "operation_name": "FAITHFUL BELIEVERS"},
    {"operation_id": 3, "operation_name": "SAMPLE OP"},
    {"operation_id": 4, "operation_name": "SAMPLE OP 2"}
]

target_id = None
for op in operations:
    if op["operation_name"] == "SAMPLE OP":
        target_id = op["operation_id"]
        break

# 打印结果
print(target_id if target_id else "未找到匹配项") # 输出3

简洁的生成器方式 #

operations = [
    {"operation_id": 2, "operation_name": "FAITHFUL BELIEVERS"},
    {"operation_id": 3, "operation_name": "SAMPLE OP"},
    {"operation_id": 4, "operation_name": "SAMPLE OP 2"}
]

# 找到就返回对应id，找不到返回None
target_id = next((op["operation_id"] for op in operations if op["operation_name"] == "SAMPLE OP"), None)
print(target_id if target_id else "未找到匹配项")

内容的提问来源于stack exchange，提问作者maestro