制作Flappy Bird练习版：管道生成计时器代码报错求助

我正在制作简易版Flappy Bird用于练习，需求是按时间间隔生成管道，后续可缩短时间间隔逐步提升难度。以下是我的pipe_Spawner脚本代码：

using System.Collections;
using System.Collections.Generic;
using UnityEngine;

public class pipe_Spawner : MonoBehaviour
{
    public GameObject pipesPrefab;
    // Start is called before the first frame update
    void Start()
    {
        
    }
    public float secsToNext -= Time.deltaTime// public lets you check it running in the inspector
    { 
    // Update is called once per frame
    void Update()//every single frame its called
    {
        secsToNext -= Time.deltaTime;  // T.dt is secs since last update
        if(secsToNext<=5) {
        secsToNext = Random.Range(8.0f, 12.0f);
        float Vertical = Random.Range(1.0f, 6.0f);
        float Horizontal = Random.Range(-7.0f, 7.0f);
        Instantiate(pipesPrefab, new Vector2(Vertical,Horizontal), Quaternion.identity);
        }
    }
}
}

当前Unity中出现以下编译错误：

• Assets\pipe_Spawner.cs(13,29): error CS1003: Syntax error, ',' expected
• Assets\pipe_Spawner.cs(13,32): error CS1002: ; expected
• Assets\pipe_Spawner.cs(14,5): error CS1519: Invalid token '{' in class, struct, or interface member declaration
• Assets\pipe_Spawner.cs(27,1): error CS1022: Type or namespace definition, or end-of-file expected

注：当前坐标为随机值仅用于测试。

错误分析与修复 #

1. 变量声明错误：类成员位置不能直接对变量执行-= Time.deltaTime操作，需先声明并初始化变量，再在方法内修改。
2. 代码块嵌套错误：错误给变量声明添加了{}，导致Update方法被非法嵌套，同时末尾多了一个冗余的闭合}。
3. 生成逻辑错误：原条件secsToNext <=5会导致游戏启动就触发生成，不符合“间隔时间到了才生成”的逻辑，应改为secsToNext <=0。

修复后的代码：

using System.Collections;
using System.Collections.Generic;
using UnityEngine;

public class pipe_Spawner : MonoBehaviour
{
    public GameObject pipesPrefab;
    // 初始生成间隔，可在Inspector面板调整
    public float spawnInterval = 3f;
    // 距离下次生成的剩余时间
    private float secsToNext;

    void Start()
    {
        // 初始化剩余时间为初始间隔
        secsToNext = spawnInterval;
    }

    void Update()
    {
        secsToNext -= Time.deltaTime;
        // 剩余时间归零时生成管道
        if(secsToNext <= 0)
        {
            // 重置剩余时间，加入随机范围增加游戏变化
            secsToNext = Random.Range(2f, spawnInterval);
            // 测试用随机坐标，后续可改为固定X轴+随机Y轴（符合Flappy Bird经典逻辑）
            float verticalPos = Random.Range(1.0f, 6.0f);
            float horizontalPos = Random.Range(-7.0f, 7.0f);
            Instantiate(pipesPrefab, new Vector2(horizontalPos, verticalPos), Quaternion.identity);
        }
    }
}

难度提升思路 #

后续要提升难度，只需在游戏过程中逐步减小spawnInterval的值即可，比如通过分数触发：

// 示例：每得10分缩短0.2秒间隔，最低限制为1秒避免过快
public void IncreaseDifficulty(int score)
{
    if(score % 10 == 0 && spawnInterval > 1f)
    {
        spawnInterval -= 0.2f;
    }
}

内容的提问来源于stack exchange，提问作者SirShrkimpalot