如何用Python将多个文件系统路径列表转为嵌套字典？

云上老周

2026-8-25

将路径列表转换为嵌套字典的Python实现

实现思路

遍历每个路径列表，逐层构建嵌套字典：从根字典出发，沿着路径的每个节点往下遍历，若节点不存在则创建空字典，直到走完整个路径的所有节点。

代码实现

def build_nested_dict(paths):
    result = {}
    for path in paths:
        current = result
        for part in path:
            # 若当前节点不存在，创建空字典
            if part not in current:
                current[part] = {}
            # 进入下一层字典
            current = current[part]
    return result

# 示例输入路径集合
paths = [
    ["root_path", "Test", "Subfolder1"],
    ["root_path", "Test", "Subfolder2"],
    ["root_path", "Test", "Subfolder3"],
    ["root_path", "Test", "Subfolder1", "Subfolder1-1"],
    ["root_path", "Test", "Subfolder1", "Subfolder1-1", "Subfolder1-1-1"]
]

# 生成嵌套字典
resulting_dict = build_nested_dict(paths)

输出结果

执行上述代码后，resulting_dict的结构与期望完全一致：

{
    "root_path": {
        "Test": {
            "Subfolder1": {
                "Subfolder1-1": {
                    "Subfolder1-1-1": {}
                } 
            },
            "Subfolder2": {},
            "Subfolder3": {},
        }
    }
}