如何在Python中隐藏input()的用户输入，自定义输入展示位置？

我需要隐藏take_stick = int(input())的默认用户输入显示，将输入内容打印到指定位置，期望输出效果如下：

Game of sticks
Player 1 enter how many sticks to remove: 2
There are 19 sticks left
Player 2 enter how many sticks to remove: 4
Must remove between 1-3 sticks! 

但目前程序会在每行之间单独显示用户输入的数字，当前代码如下：

def main():
    print("Game of sticks")
    player_turn = 1
    starting_sticks = 21
    sticks_left = starting_sticks

    while True:
        if starting_sticks == 21:
            if sticks_left < 1:
                print("There are", sticks_left, "sticks left")
            take_stick = int(input())

            if take_stick < 1 or take_stick > 3:
                print("Must remove between 1-3 sticks!")

            elif take_stick >= 1 and take_stick <= 3:
                sticks_left -= take_stick
            if sticks_left == 21:
                print("Player", player_turn, "enter how many sticks to remove:", take_stick)
                player_turn += 1
                if player_turn == 3:
                    player_turn -= 2
            elif sticks_left != 1:
                print("Player", player_turn, "enter how many sticks to remove:", take_stick)
                player_turn += 1
                if player_turn == 3:
                    player_turn -= 2
                print("There are", sticks_left, "sticks left")

            if sticks_left <= 0:
                print()
                print("Player", (player_turn), "lost the game!")
                break
main()

解决方法 #

核心是先打印输入提示（不换行），再获取输入，这样用户输入的内容会直接跟在提示文本后面，无需事后重复打印，同时避免输入内容单独占一行。另外需要修正原代码中冗余的starting_sticks ==21判断（该变量从未修改，条件永远成立），梳理逻辑流程：

修改后的代码：

def main():
    print("Game of sticks")
    player_turn = 1
    sticks_left = 21

    while True:
        # 先打印提示，end=''让光标停在提示末尾，不换行
        print(f"Player {player_turn} enter how many sticks to remove: ", end='')
        # 直接获取输入，此时输入会显示在提示后面
        take_stick = int(input())

        # 处理非法输入
        if take_stick < 1 or take_stick > 3:
            print("Must remove between 1-3 sticks!")
            continue  # 不切换玩家，重新输入

        # 合法输入，减少剩余棍子数
        sticks_left -= take_stick

        # 检查是否游戏结束
        if sticks_left <= 0:
            print(f"\nPlayer {player_turn} lost the game!")
            break

        # 打印剩余棍子数
        print(f"There are {sticks_left} sticks left")

        # 切换玩家
        player_turn = 2 if player_turn == 1 else 1

main()

关键说明：

1. print(..., end='')：取消默认的换行符，让输入光标停在提示文本后面，用户输入的数字会直接显示在提示末尾，符合期望格式。
2. 移除了原代码中冗余的starting_sticks判断，简化逻辑。
3. 用continue处理非法输入，避免错误切换玩家。
4. 优化玩家切换逻辑，用player_turn = 2 if player_turn ==1 else 1替代繁琐的加减操作。

内容的提问来源于stack exchange，提问作者emkay