使用BeautifulSoup解析网页遇AttributeError: ResultSet无find_all属性求助

尝试从class为name的<p>标签中提取内部<a>标签时，出现以下错误：

AttributeError : ResultSet object has no attribute 'find_all'

目标HTML代码片段 #

<div class="last_episodes loaddub">
<ul class="items">
<li>
<div class="img">
<a href="/digimon-ghost-game-episode-36" title="Digimon Ghost Game">
<img alt="Digimon Ghost Game" src="https://gogocdn.net/cover/digimon-ghost-game.png"/>
<div class="type ic-SUB"></div>
</a>
</div>
<p class="name"><a href="/digimon-ghost-game-episode-36" title="Digimon Ghost Game">Digimon Ghost Game</a></p>
<p class="episode">Episode 36</p>
</li>
<li>
<div class="img">
<a href="/waccha-primagi-episode-41" title="Waccha PriMagi!">
<img alt="Waccha PriMagi!" src="https://gogocdn.net/cover/waccha-primagi.png"/>
<div class="type ic-SUB"></div>
</a>
</div>
<p class="name"><a href="/waccha-primagi-episode-41" title="Waccha PriMagi!">Waccha PriMagi!</a></p>
<p class="episode">Episode 41</p>
</li>
<li>
<div class="img">
<a href="/one-piece-episode-1027" title="One Piece">
<img alt="One Piece" src="https://gogocdn.net/images/anime/One-piece.jpg"/>
<div class="type ic-SUB"></div>
</a>
</div>
<p class="name"><a href="/one-piece-episode-1027" title="One Piece">One Piece</a></p>
<p class="episode">Episode 1027</p>
</li>
<!-- 剩余HTML片段省略 -->
</ul>
</div>

初始代码 #

from urllib import response
from venv import create
from bs4 import BeautifulSoup
import requests

url = "https://gogoanime.gg?page=1"

req = requests.get(url)
Response = req.content
soup = BeautifulSoup(Response, 'html.parser')


p_tags = soup.find_all('p', class_='name')  
a_tags = p_tags.find_all('a')
for link in a_tags:
    links = link.get('href')
    print(links)

尝试过的修改（未解决） #

修改1： #

p_tags = soup.find_all('p', class_='name')  
for a_tags in p_tags.find_all('a')
    print(a_tags)

修改2：能获取a标签但提取href报错，仅返回最后一个结果 #

p_tags = soup.find_all('p', class_='name')  
for a in p_tags:
    a_tags = a.find_all('a')
    print(len(a_tags))

解决方案 #

错误原因 #

soup.find_all('p', class_='name')返回的是ResultSet对象（类似列表的集合），它是多个Tag对象的容器，不能直接调用find_all()方法。必须遍历这个集合，对每个单独的<p>标签（Tag对象）执行查找操作。

正确代码1：遍历每个p标签提取a标签 #

from bs4 import BeautifulSoup
import requests

url = "https://gogoanime.gg?page=1"

req = requests.get(url)
soup = BeautifulSoup(req.content, 'html.parser')

p_tags = soup.find_all('p', class_='name')
for p in p_tags:
    # 每个p标签内只有一个a标签，用find()更高效
    a_tag = p.find('a')
    if a_tag:
        href = a_tag.get('href')
        print(href)

正确代码2：用CSS选择器一步到位（更简洁） #

直接通过CSS选择器定位到p.name内部的<a>标签，无需分步处理：

from bs4 import BeautifulSoup
import requests

url = "https://gogoanime.gg?page=1"

req = requests.get(url)
soup = BeautifulSoup(req.content, 'html.parser')

# 直接选择所有class为name的p标签下的a标签
a_tags = soup.select('p.name a')
for a in a_tags:
    href = a.get('href')
    print(href)

针对修改2的修复 #

修改2中a.find_all('a')返回的仍是ResultSet，需要从中取出单个a标签再提取href：

p_tags = soup.find_all('p', class_='name')  
for p in p_tags:
    a_tags = p.find_all('a')
    # 遍历每个a标签（虽然这里每个p只有一个）
    for a in a_tags:
        print(a.get('href'))

内容的提问来源于stack exchange，提问作者Omega500