Python代码重复打印问题排查：如何实现仅打印一次？

Hey there! I see the issue right away—your code is printing the same Version and Source data multiple times because you've placed the print statement inside a loop that iterates over all child nodes of air:EDS_AirCheckInRQ. Let me break this down and fix it for you.

Why You're Getting Duplicate Output #

Looking at your code:

• You first fetch all child nodes of air:EDS_AirCheckInRQ into the nodes variable
• Then you loop through each child node with for x in nodes
• Inside the loop, you repeatedly query and print the same Version attribute and com:Source node

Since air:EDS_AirCheckInRQ has 6 child nodes, the loop runs 6 times—hence 6 identical lines of output.

Fixed Code #

Move the print statement outside the loop, because Version and com:Source are properties of the parent air:EDS_AirCheckInRQ node (not its children). If you still need to process the child nodes, keep the loop but use it for child-specific data:

from simplified_scrapy import SimplifiedDoc, utils #simplified_scrapy is framework for extracting data
xml = utils.getFileContent('check_in.xml')
doc = SimplifiedDoc(xml) #SimplifiedDoc is a library for parsing data such as HTML and XML

# Grab the main parent node once
main_checkin_node = doc.select('air:EDS_AirCheckInRQ')

# Print the static data ONCE, outside the loop
print(main_checkin_node['Version'], main_checkin_node.select('com:Source'))

# If you need to process child nodes, do that here (optional)
child_nodes = main_checkin_node.children
for node in child_nodes:
    # Example: Print each child node's tag for debugging
    print(f"Child node tag: {node.tag}")

What This Does #

• The Version and com:Source values are fetched once from the parent node and printed a single time
• The loop (if kept) now handles only child node-specific logic, without repeating the static parent data

This will give you the single output line you want, while still letting you work with the child nodes if needed.

内容的提问来源于stack exchange，提问作者Minhaj Khan