如何移除嵌套对象中available为false的components子对象？

你需要处理嵌套JSON里product.components这个键值对对象，移除其中所有available属性为false的子对象，同时保留原JSON结构不变。下面提供两种主流编程语言的实现方案：

JavaScript 实现 #

通过遍历components的所有键，判断子对象的available值，仅保留符合条件的条目：

// 假设原始JSON已解析为对象
const data = {
    "msg": "OK",
    "blueprint": {
        "result": "OK",
        "blueprint": {
            "id": "a2e63ee01401aaeca78be023dfbb8c59",
            "product": {
                "productName": "Test Product",
                "productId": "AS_12-01",
                "description": "Test Descr.",
                "childProducts": [
                    {"childId": "T1", "parent": "8c59"},
                    {"childId": "T5", "parent": "8c7e"}
                ],
                "components": {
                    "component1": {"compId": "C2", "leadTime": 21, "available": false},
                    "component2": {"compId": "C5", "leadTime": 3, "available": true},
                    "component3": {"compId": "C6", "leadTime": 12, "available": false},
                    "component4": {"compId": "C8", "leadTime": 5, "available": true}
                }
            },
            "owner": "dummy",
            "name": "du_test"
        }
    }
};

// 过滤components对象
const filteredComponents = {};
for (const key in data.blueprint.blueprint.product.components) {
    const component = data.blueprint.blueprint.product.components[key];
    if (component.available) {
        filteredComponents[key] = component;
    }
}

// 替换原对象的components字段
data.blueprint.blueprint.product.components = filteredComponents;

// 输出处理后的结果
console.log(JSON.stringify(data, null, 2));

Python 实现 #

用字典推导式快速筛选符合条件的键值对，直接替换原字段：

import json

# 原始JSON字符串
json_str = '''{
    "msg": "OK",
    "blueprint": {
        "result": "OK",
        "blueprint": {
            "id": "a2e63ee01401aaeca78be023dfbb8c59",
            "product": {
                "productName": "Test Product",
                "productId": "AS_12-01",
                "description": "Test Descr.",
                "childProducts": [
                    {"childId": "T1", "parent": "8c59"},
                    {"childId": "T5", "parent": "8c7e"}
                ],
                "components": {
                    "component1": {"compId": "C2", "leadTime": 21, "available": false},
                    "component2": {"compId": "C5", "leadTime": 3, "available": true},
                    "component3": {"compId": "C6", "leadTime": 12, "available": false},
                    "component4": {"compId": "C8", "leadTime": 5, "available": true}
                }
            },
            "owner": "dummy",
            "name": "du_test"
        }
    }
}'''

# 解析JSON为字典
data = json.loads(json_str)

# 过滤components：仅保留available为True的条目
data['blueprint']['blueprint']['product']['components'] = {
    key: comp for key, comp in data['blueprint']['blueprint']['product']['components'].items()
    if comp['available']
}

# 输出处理后的结果
print(json.dumps(data, indent=2))

内容的提问来源于stack exchange，提问作者AbreQueVoy