如何遍历包含None类型的嵌套数组并跳过None元素

你遇到的错误是因为当element为None时，尝试执行element[0]——None不支持下标访问。要跳过这些空元素，只需在访问下标前先判断元素是否为None即可。

修复后的代码 #

field = [ [['PEASH', 5], None, None, None, None, None, ['ZOMB', 15]],
          [['PEASH', 5], None, None, None, None, None, ['ZOMB', 15]],
          [None, None, None, None, None, None, None],
          [None, None, None, None, None, None, None],
          [None, None, None, None, None, None, None] ]

num_rows=len(field)
num_columns=len(field[0])

lane = 0
row_counter = -1
column_counter = -1
for row in range(num_rows):
    row_counter += 1
    print('rowcounter is at',row_counter)
    print(row)
    column_counter = -1  # 重置列计数器，避免跨行列计数累加错误
    for column in range(num_columns):
        column_counter += 1

        element = field[row][column] 
        print(element)
        # 先判断元素不为None，再检查类型
        if element is not None and element[0] == 'PEASH':
            print('yes there is a peashooter in',row_counter,column_counter)

核心修改说明 #

• 跳过None元素：增加element is not None的判断，确保只有非空元素才会执行下标访问，直接避免TypeError。
• 可选写法：也可以用continue直接跳过空元素，逻辑更清晰：

  element = field[row][column] 
  print(element)
  if element is None:
      continue  # 跳过当前列，直接进入下一列循环
  if element[0] == 'PEASH':
      print('yes there is a peashooter in',row_counter,column_counter)
  

• 额外优化：原代码中column_counter会在所有行中持续累加，导致列计数混乱。把column_counter = -1放到外层循环（每行开始时），可以让每行列计数从0重新开始。

内容的提问来源于stack exchange，提问作者user19198861