如何消除代码中匹配后的重复学生记录？循环逻辑问题排查

匹配到“1st name”后按逻辑应退出循环，但输出中仍出现“Student Created inside Else 1st name”这类记录，请求消除该错误记录。

student_for_admission = [{"student_name": "1st name", "other_key": "other_val"},{"student_name": "johndoe", "student":"other_val"}]
Student_eligible = [{"name": "1st name", "other_key": "other_val1", "another_key": "another_val2"},{"name": "2nd name", "other_key": "other_val", "another_key": "another_val"},{"name": "3rd name", "other_key": "other_val", "another_key": "another_val"}]
student_created=0
student_updated=0
student_skipped=0
for student in student_for_admission:
    for eligible in Student_eligible:
        if eligible["name"] == student["student_name"]:
            # Matching student found
            print("Student updated " + eligible["name"])
            print("Skipped " + eligible["name"])
            student_skipped += 1
            print(student_skipped)
            print("Before break")
            break
            print("After break")
        else:
            # Create Student
            print("Student Created inside Else "+ eligible["name"])
            student_created += 1

Student updated 1st name
Skipped 1st name
1
Before break
Student Created inside Else 1st name
Student Created inside Else 2nd name
Student Created inside Else 3rd name

代码逻辑存在错误：内层循环中每一次eligible与当前student不匹配时，都会执行else里的创建操作，而非遍历完所有eligible都未找到匹配才执行创建。

• 第一个学生“1st name”匹配到第一个eligible后退出内层循环，这部分逻辑正常；
• 第二个学生“johndoe”遍历所有3个eligible都未匹配，因此每一次不匹配都会触发else分支，导致输出三条创建记录，其中就包含“1st name”的那条。

添加标记变量记录是否找到匹配学生，仅当遍历完所有eligible都未找到匹配时，才执行创建操作：

student_for_admission = [{"student_name": "1st name", "other_key": "other_val"},{"student_name": "johndoe", "student":"other_val"}]
Student_eligible = [{"name": "1st name", "other_key": "other_val1", "another_key": "another_val2"},{"name": "2nd name", "other_key": "other_val", "another_key": "another_val"},{"name": "3rd name", "other_key": "other_val", "another_key": "another_val"}]
student_created=0
student_updated=0
student_skipped=0

for student in student_for_admission:
    found = False  # 标记是否找到匹配学生
    for eligible in Student_eligible:
        if eligible["name"] == student["student_name"]:
            # 找到匹配学生
            print("Student updated " + eligible["name"])
            print("Skipped " + eligible["name"])
            student_skipped += 1
            print(student_skipped)
            print("Before break")
            found = True
            break
    # 遍历完所有eligible都未找到匹配，才创建学生
    if not found:
        print("Student Created " + student["student_name"])
        student_created += 1

Student updated 1st name
Skipped 1st name
1
Before break
Student Created johndoe

内容的提问来源于stack exchange，提问作者An_pack