Python均值计算器函数异常：输入a为2却不执行对应计算逻辑

编写了一个用于计算均值的Python函数part1，测试时输入变量a的值为2，但代码判定a不等于2，无法执行均值计算逻辑，使用PyCharm作为开发环境。

代码如下：

def part1(Answer1, Answer2):
    x=Answer1+Answer2
    y=x/2
    print(y)

print("What are your numbers? 2 max")
a=input("How many numbers would you like? :")
Answer1=input("What is your first number? :")
Answer2=input("What is your second number? :")

if a==2:
    part1(Answer1, Answer2)
else:
    print(a)

• 核心原因：类型不匹配
  input()函数返回的内容是字符串类型，你输入的"2"是字符串，而判断条件里和整数2做相等比较，"2" == 2的结果为False，因此不会进入均值计算的分支。

• 额外隐藏问题
  就算解决了a的类型问题，Answer1和Answer2同样是字符串类型，直接用+运算会执行字符串拼接而非数值相加。比如输入1和2，会得到"12"，再除以2得到6.0，不符合均值计算的预期。

修正后的代码 #

def part1(Answer1, Answer2):
    x = Answer1 + Answer2
    y = x / 2
    print(y)

print("What are your numbers? 2 max")
# 将输入的a转换为整数类型
a = int(input("How many numbers would you like? :"))
# 将输入的数值转换为浮点数，支持小数输入
Answer1 = float(input("What is your first number? :"))
Answer2 = float(input("What is your second number? :"))

if a == 2:
    part1(Answer1, Answer2)
else:
    print(a)

内容的提问来源于stack exchange，提问作者curious