Python代码返回换行及二进制编码空串问题，请求调试帮助

一、编码功能返回空串的问题及修复 #

核心bug分析 #

1. 字符遍历逻辑错误：编码部分用string.split()分割输入，会把无空格的输入（如"A)"）当成单个元素，而你的匹配列表都是单个字符，导致循环中没有匹配项，encoded始终为空。
2. index()方法调用错误：所有symbols.index()、upper.index()等调用都缺少要查找的字符参数c，即使遍历逻辑正确也会触发TypeError。
3. 结果拼接冗余空格：直接用" " + ibin拼接会导致结果开头多出一个空格，影响输出格式。

修复后的完整代码 #

import json

symbols = [" ", "!", '"', "#", "$", "%", "&", "'", "(", ")", "*", "+", ",", "-", ".", "/", "0", "1", "2", "3", "4", "5", "6", "7", "8", "9", ":", ";", "<", "=", ">", "?", "@"]
letters = ["a", "b", "c", "d", "e", "f", "g", "h", "i", "j", "k", "l", "m", "n", "o", "p", "q", "r", "s", "t", "u", "v", "w", "x", "y", "z"]
upper = list(map(lambda x: x.upper(), letters))
after = ["{", "|", "}", "~"]
symbol_sub = 32
upper_sub = 65
lower_sub = 97
after_sub = 123

choice = input("Do you want to encode text, or decode it? e, or d? ").lower()
if choice == 'e':
    string = input("Type in your text: ")
    encoded_parts = []
    # 遍历输入的每个单个字符，而非按空格分割后的元素
    for c in string:
        if c in symbols:
            i = symbols.index(c) + symbol_sub
            ibin = bin(i).split('0b')[1]
            encoded_parts.append(ibin)
        elif c in upper:
            i = upper.index(c) + upper_sub
            ibin = bin(i).split('0b')[1]
            encoded_parts.append(ibin)
        elif c in letters:
            i = letters.index(c) + lower_sub
            ibin = bin(i).split('0b')[1]
            encoded_parts.append(ibin)
        elif c in after:
            i = after.index(c) + after_sub
            ibin = bin(i).split('0b')[1]
            encoded_parts.append(ibin)
    # 用空格连接所有二进制串，避免开头冗余空格
    encoded = " ".join(encoded_parts)
    print(encoded)

elif choice == 'd':
    string = input("Please input your binary code, each binary string separated by spaces: ")
    allbits = string.split(' ')
    decoded = ''
    for i in allbits:
        b10 = int(i, 2)
        if b10 - after_sub < 0:
            if b10 - lower_sub < 0:
                if b10 - upper_sub < 0:
                    decoded += symbols[b10 - symbol_sub]
                else:
                    decoded += upper[b10 - upper_sub]
            else:
                decoded += letters[b10 - lower_sub]
        else:
            decoded += after[b10 - after_sub]
    print(decoded)

测试输入"A)"时，输出为1000001 101001，符合预期。

二、代码返回换行的问题 #

Python的print()函数默认会在输出末尾添加换行符，这是标准行为。如果不需要输出末尾的换行，可以修改print语句为：

print(encoded, end='')

如果是指输出内容中出现意外换行，检查输入时是否误输入了换行符，或者确保处理字符时没有引入换行相关的字符。

内容的提问来源于stack exchange，提问作者Dark Shadow