如何提取两个指定字符串间的多段目标子串？技术实现求助

Got it, let's fix this substring extraction issue for you. The core problem here is pulling out repeated key-value pairs (name/phone) from a string that looks like a simplified JSON object. Here's a straightforward approach using Python's regex module, which is perfect for this kind of pattern matching:

Step 1: Clean Up the Input String (if needed) #

First, notice your input uses Chinese quotation marks (‘/’) instead of standard English ones ('). These will break regex matching, so we'll first convert them to English quotes:

one_string = " ‘name’:’john’,’phone’:’8947467’,’name’:’anthony’,’phone’:’74729’ "
# Replace Chinese quotes with English ones
cleaned_string = one_string.replace('‘', "'").replace('’', "'")

Step 2: Extract Names and Phones with Regex #

We'll use re.findall() to capture all matching values. The regex pattern 'name':'(.*?)' targets the value between 'name':' and the next ' — the .*? is a non-greedy match, which ensures we stop at the first closing quote instead of grabbing everything until the last quote in the string.

Here's the full code:

import re

# Original input string
one_string = " ‘name’:’john’,’phone’:’8947467’,’name’:’anthony’,’phone’:’74729’ "

# Clean up quotation marks
cleaned_string = one_string.replace('‘', "'").replace('’', "'")

# Extract all names
names = re.findall(r"'name':'(.*?)'", cleaned_string)
# Extract all phones
phones = re.findall(r"'phone':'(.*?)'", cleaned_string)

# Format output as you requested
formatted_names = ','.join(f"'{name}'" for name in names)
formatted_phones = ','.join(f"'{phone}'" for phone in phones)

print(f"names = {formatted_names}")
print(f"phones = {formatted_phones}")

What This Does: #

• re.findall() returns a list of all matched values, so names will be ['john', 'anthony'] and phones will be ['8947467', '74729']
• The join() and f-strings format the lists into the exact string output you want: names = 'john','anthony' and phones = '8947467','74729'

Alternative: Parse as a Dictionary List (More Robust) #

If your input string is consistently formatted, you could also convert it into a proper list of dictionaries for more flexibility. Here's how:

import re
import ast

cleaned_string = one_string.replace('‘', "'").replace('’', "'")
# Split into individual key-value pairs and wrap into list of dicts
items = re.findall(r"'name':'(.*?)','phone':'(.*?)'", cleaned_string)
records = [{'name': name, 'phone': phone} for name, phone in items]

names = [record['name'] for record in records]
phones = [record['phone'] for record in records]

This approach is better if you need to work with the name-phone pairs together later on.

内容的提问来源于stack exchange，提问作者Johnny