Python 3.10自定义游戏：无法将武器名称转为对应整数数值求助

开发的Python 3.10小型游戏中，希望玩家输入武器名称（如axe）时，将weapon变量转换为对应的伤害值整数（如25），而非保留字符串类型，目前无法实现该转换逻辑，寻求解决方法。

原始代码：

goblin = 20

dagger = 10

sword = 15

axe = 25

print('There is a goblin up ahead, what weapon would you like to choose? A dagger, a sword, or an axe?')

weapon = input()


print('You look around, and pick up the ' + weapon)


if weapon > goblin:

    #A small game
    goblin = 20
    dagger = 10
    sword = 15
    axe = 25

    print('There is a goblin up ahead, what weapon would you like to choose? A dagger, a sword, or an axe?')
    weapon = input()

    print('You look around, and pick up the ' + weapon)

    if weapon > goblin:
        print('You swing the ' + weapon + ' at the goblin, cutting its head off in succession!')

    else:
        print('You swing the ' + weapon + ' at the goblin, but fail to do enough damage. You are defeated.')


    print('You swing the ' + weapon + ' at the goblin, cutting its head off in succession!')

else:
    print('You swing the ' + weapon + ' at the goblin, but fail to do enough damage. You are defeated.')

最简洁可靠的方式是用字典建立武器名称到伤害值的映射，既可以快速完成字符串到整数的转换，还能轻松处理非法输入的情况。

修改后的代码示例：

# 建立武器名称与伤害值的映射字典
weapon_damage_map = {
    'dagger': 10,
    'sword': 15,
    'axe': 25
}
goblin_health = 20

print('There is a goblin up ahead, what weapon would you like to choose? A dagger, a sword, or an axe?')
# 转小写+去空格处理，兼容玩家输入大小写不同、带空格的情况
player_choice = input().strip().lower()

# 验证输入是否合法
if player_choice not in weapon_damage_map:
    print('Invalid weapon! You hesitate and the goblin attacks. You are defeated.')
else:
    weapon_name = player_choice
    weapon_dmg = weapon_damage_map[player_choice]
    print(f'You look around, and pick up the {weapon_name}')

    # 用武器伤害值与哥布林生命值比较
    if weapon_dmg > goblin_health:
        print(f'You swing the {weapon_name} at the goblin, cutting its head off in succession!')
    else:
        print(f'You swing the {weapon_name} at the goblin, but fail to do enough damage. You are defeated.')

核心改动说明 #

• 使用字典替代分散的变量，直接关联武器名称和对应伤害值，逻辑更紧凑
• 用strip().lower()处理输入，去除空格并统一为小写，避免因输入Axe或 dagger（带空格）导致匹配失败
• 增加非法输入判断，处理玩家输入错误武器名的场景
• 拆分出weapon_name（用于文本输出）和weapon_dmg（用于数值比较）两个变量，同时满足展示和逻辑判断需求
• 移除原代码中重复的变量定义和冗余逻辑，简化整体结构

内容的提问来源于stack exchange，提问作者Kosstheboss123