如何将多个含arrayResult的JSON字符串合并为单个JSON数组？

完整实现代码 #

using Newtonsoft.Json;
using Newtonsoft.Json.Linq;
using System;
using System.Collections.Generic;

namespace ConsoleApp5
{
    class Program
    {
        static void Main(string[] args)
        {
            Console.WriteLine("Hello World!");
            MergeJsonResult();
        }
        private static void MergeJsonResult()
        {
            List<string> jsonResult = new List<string>();
            jsonResult.Add("{\n  \"arrayResult\": [\n    {\"Item1\": \"123\",\n    \"Item2\": \"858\",\n    \"Item3\": \"789\"\n    },\n    {\"Item1\": \"2588\",\n    \"Item2\": \"858\",\n    \"Item3\": \"587\"\n    }\n  ]\n}");
            jsonResult.Add("{\n  \"arrayResult\": [\n    {\"Item1\": \"123\",\n    \"Item2\": \"858\",\n    \"Item3\": \"789\"\n    },\n    {\"Item1\": \"2588\",\n    \"Item2\": \"858\",\n    \"Item3\": \"587\"\n    }\n  ]\n}");
            jsonResult.Add("{\n  \"arrayResult\": [\n    {\"Item1\": \"123\",\n    \"Item2\": \"858\",\n    \"Item3\": \"789\"\n    },\n    {\"Item1\": \"2588\",\n    \"Item2\": \"858\",\n    \"Item3\": \"587\"\n    }\n  ]\n}");

            // 初始化存储所有合并元素的数组
            JArray mergedArray = new JArray();

            foreach (var eachJson in jsonResult)
            {
                // 解析单个JSON字符串为JObject
                JObject jsonObj = JObject.Parse(eachJson);
                // 取出当前JSON中的arrayResult数组
                JArray currentArray = (JArray)jsonObj["arrayResult"];
                // 将当前数组的所有元素添加到合并数组中
                mergedArray.Merge(currentArray);
            }

            // 创建最终的根JSON对象
            JObject finalResult = new JObject();
            finalResult["arrayResult"] = mergedArray;

            // 序列化为格式化的JSON字符串并输出
            string mergedJson = finalResult.ToString(Formatting.Indented);
            Console.WriteLine(mergedJson);
        }
    }
}

实现说明 #

1. 借助LINQ to JSON API：用JObject和JArray直接操作JSON结构，无需定义实体类，适配动态JSON格式场景。
2. 遍历解析与合并：逐个解析输入的JSON字符串，提取每个字符串里的arrayResult数组，通过Merge方法批量将子数组元素合并到总数组中，也可以用循环逐个添加元素（mergedArray.Add(item)）。
3. 生成最终JSON：创建根对象并将合并后的数组赋值给arrayResult键，最后序列化为带缩进的格式化JSON字符串。

输入示例 #

• String1

{
  "arrayResult": [
    {
      "Item1": "123",
      "Item2": "858",
      "Item3": "789"
    },
    {
      "Item1": "2588",
      "Item2": "858",
      "Item3": "587"
    }
  ]
}

• String2

{
  "arrayResult": [
    {
      "Item1": "123",
      "Item2": "858",
      "Item3": "789"
    },
    {
      "Item1": "2588",
      "Item2": "858",
      "Item3": "587"
    }
  ]
}

• String3

{
  "arrayResult": [
    {
      "Item1": "123",
      "Item2": "858",
      "Item3": "789"
    },
    {
      "Item1": "2588",
      "Item2": "858",
      "Item3": "587"
    }
  ]
}

输出结果 #

{
  "arrayResult": [
    {
      "Item1": "123",
      "Item2": "858",
      "Item3": "789"
    },
    {
      "Item1": "2588",
      "Item2": "858",
      "Item3": "587"
    },
    {
      "Item1": "123",
      "Item2": "858",
      "Item3": "789"
    },
    {
      "Item1": "2588",
      "Item2": "858",
      "Item3": "587"
    },
    {
      "Item1": "123",
      "Item2": "858",
      "Item3": "789"
    },
    {
      "Item1": "2588",
      "Item2": "858",
      "Item3": "587"
    }
  ]
}

内容的提问来源于stack exchange，提问作者Rupesh