求助:使用JavaScript更新多个文本片段实例失败的解决办法
多文本片段同步更新失败的解决方法
你的核心问题是HTML里重复使用了同一个ID——ID在HTML规范里必须是唯一的,document.getElementById()只会返回第一个匹配到的元素,所以只有第一个标签里的名字能更新。
解决步骤很简单:
- 把所有要更新的span标签的
id="initname"改成class="initname",同时去掉原代码里span标签上多余的分号(原代码里<span id="initname";>的分号是语法错误) - 修改
changeText函数,获取所有带initname类的元素,循环更新每个元素的内容
修改后的完整代码如下:
完整可运行代码
<!DOCTYPE html> <html> <head> <style> body { font-family: Arial; width: 75%; margin-right: auto; margin-left: auto; } .tab { overflow: hidden; border: 1px solid #ccc; background-color: #f1f1f1; } .tab button { background-color: inherit; float: left; border: none; outline: none; cursor: pointer; padding: 15px 15px; transition: 0.2s; font-size: 18px; } .tab button:hover { background-color: #ddd; } .tab button.active { background-color: #ccc; } .tabcontent { display: none; padding: 5px 5px; border: 1px solid #ccc; border-top: none; } </style> </head> <body> <h2>Test thing</h2> <p> <form method="post"> <input type="text" onkeyup="changeText(this)" name="first name" placeholder="Enter Your Name" required="required" class="input-txt" /> </form> </p> <p>tabs of sentences</p> <div class="tab"> <button class="tablinks" onclick="openTab(event, 'Tab 1')">Tab 1</button> <button class="tablinks" onclick="openTab(event, 'Tab 2')">Tab 2</button> <button class="tablinks" onclick="openTab(event, 'Tab 3')">Tab 3</button> </div> <div id="Tab 1" class="tabcontent"> <p>Hello, my name is <b><span class="initname">First and Last</span></b> number 1 and I really wish all instances of my name would update when I type in the above text field.</p> </div> <div id="Tab 2" class="tabcontent"> <p>Hello, my name is <b><span class="initname">First and Last</span></b> number 2 and I really wish all instances of my name would update when I type in the above text field.</p> </div> <div id="Tab 3" class="tabcontent"> <p>Hello, my name is <b><span class="initname">First and Last</span></b> number 3 and I really wish all instances of my name would update when I type in the above text field.</p> </div> <script> function openTab(evt, tabName) { var i, tabcontent, tablinks; tabcontent = document.getElementsByClassName("tabcontent"); for (i = 0; i < tabcontent.length; i++) { tabcontent[i].style.display = "none"; } tablinks = document.getElementsByClassName("tablinks"); for (i = 0; i < tablinks.length; i++) { tablinks[i].className = tablinks[i].className.replace(" active", ""); } document.getElementById(tabName).style.display = "block"; evt.currentTarget.className += " active"; } // 优化后的更新函数,遍历所有目标元素 function changeText(element) { document.querySelectorAll('.initname').forEach(el => { el.textContent = element.value; }); } </script> </body> </html>
额外说明
querySelectorAll('.initname')是更现代的元素选择方式,返回的是一个节点列表,可以用forEach直接遍历;如果习惯旧写法,也可以用document.getElementsByClassName('initname'),然后用for循环遍历更新,效果完全一致。
内容的提问来源于stack exchange,提问作者CQC
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