如何将路由列表中的元组路径转换为连续节点列表？

你可以通过以下几种Python方法实现格式转换：

方法一：嵌套列表推导式（简洁高效） #

routes = [
    [(0, 1), (1, 6), (6, 7), (7, 10), (10, 9), (9, 0)],
    [(0, 2), (2, 3), (3, 4), (4, 5), (5, 0)],
    [(0, 8), (8, 0)]
]

routes_new = [[path[0][0]] + [t[1] for t in path] for path in routes]
print(routes_new)

方法二：循环遍历（直观易懂） #

routes = [
    [(0, 1), (1, 6), (6, 7), (7, 10), (10, 9), (9, 0)],
    [(0, 2), (2, 3), (3, 4), (4, 5), (5, 0)],
    [(0, 8), (8, 0)]
]

routes_new = []
for path in routes:
    new_path = [path[0][0]]
    for tup in path:
        new_path.append(tup[1])
    routes_new.append(new_path)
print(routes_new)

两种方法执行后都会得到目标格式的列表：

[[0, 1, 6, 7, 10, 9, 0], [0, 2, 3, 4, 5, 0], [0, 8, 0]]

内容的提问来源于stack exchange，提问作者iviuffek