如何关联函数实现从排列结果中匹配并输出指定目标数字

Here's how to link your two functions to capture the target number and output the required result:

Step 1: Adjust find_key to Generate String Permutations #

Your current find_key returns tuples of characters (e.g., ('4','3','2','1')), but bool_check expects a string. Modify the function to join each tuple into a string:

from itertools import product

def bool_check(x):
    # Simplified to direct comparison
    return x == "4321"

def find_key(different_dig, quantity_dig):
    chars = list(different_dig)
    perms = []
    for c in product(chars, repeat=quantity_dig):
        # Combine tuple elements into a single string
        perms.append(''.join(c))
    return perms

Step 2: Iterate Through Permutations and Check for Match #

Loop through the generated permutations, use bool_check to test each one, and print the result when a match is found:

# Generate all permutations
all_permutations = find_key("1234", 4)

# Check each candidate
for candidate in all_permutations:
    if bool_check(candidate):
        print(True)
        print(candidate)
        break  # Stop searching once target is found

Optional: Use itertools.permutations for Unique Orderings #

If you only want permutations with no repeated digits (which fits "4321"), replace product with permutations—this is more efficient as it avoids duplicate combinations:

from itertools import permutations

def find_key(different_dig, quantity_dig):
    perms = []
    # permutations generates unique orderings without repetition
    for c in permutations(different_dig, quantity_dig):
        perms.append(''.join(c))
    return perms

Running the code will output:

True
4321

内容的提问来源于stack exchange，提问作者The Vinchi