Python剪刀石头布程序输入选择无响应问题求助

问题根源 #

• 拼写错误：代码中多处把scissor写成了sicssor，当电脑随机选中scissor时，对应的判断条件无法触发，程序没有任何输出，导致你误以为输入后没响应。
• 逻辑异常：玩家获胜时直接执行break终止循环，违背了最多玩5次的设定。
• 其他小错误：vaid应为valid，loose应为lose（loose是“松散的”，lose才是“输掉”的正确拼写）。

修正后的代码 #

import random
print('Hey Lets play rock paper scissor ')
number_of_tries = 0
options = ['rock', 'paper', 'scissor']  # 提前定义列表，避免循环内重复创建
while number_of_tries < 5:
    hand = random.choice(options)
    dash = str(input("whats your pick ")).lower()
    number_of_tries += 1
    
    if dash not in options:
        print('not a valid option')
    elif dash == "rock":
        if hand == 'paper':
            print(f'you lost, the computer selected {hand}')
        elif hand == dash:
            print(f'its a tie the computer selected {hand}')
        elif hand == "scissor":
            print(f'you win the computer selected {hand}')
    elif dash == "scissor":
        if hand == "rock":
            print(f'you lose the computer selected {hand}')
        elif hand == "scissor":
            print(f'its a tie the computer selected {hand}')
        elif hand == "paper":
            print(f'you win the computer selected {hand}')
    elif dash == "paper":
        if hand == "scissor":
            print(f'you lost the computer selected {hand}')
        elif hand == "paper":
            print(f'its a tie the computer selected {hand}')
        elif hand == "rock":
            print(f'you win the computer selected {hand}')
print("the end")

额外优化说明 #

• 将选项列表移到循环外定义，避免每次循环重复创建相同列表，提升代码效率。
• 把独立的if判断改成elif，避免不必要的条件校验，逻辑更严谨。

内容的提问来源于stack exchange，提问作者Kev J