如何实现重复Try Except块，直至用户输入的除数不为0？

Got it, the problem with your current code is that it only runs the input and calculation sequence once. If the user enters 0 as the divisor, it just shows the error message and terminates immediately. To make it repeat until a non-zero divisor is provided, we can wrap the input and try/except block in an infinite loop that exits only when the division succeeds.

Modified Code (Core Solution) #

def in_num():
    a = int(input('Enter a number: '))
    b = int(input('Enter another number: '))
    return a, b

# Loop indefinitely until valid division occurs
while True:
    x, y = in_num()
    try:
        print(f'The Answer of {x}/{y} is {x/y}')
        break  # Exit the loop once calculation is successful
    except ZeroDivisionError:
        print('Cant divide by zero. Please try again.')

How It Works: #

• We use a while True loop to create an infinite cycle of input and calculation attempts.
• When the division runs without throwing a ZeroDivisionError, we print the result and use break to exit the loop.
• If the user enters 0 as the divisor, the exception is caught, we print an error message, and the loop restarts to prompt for new inputs.

Bonus: Handle Invalid Integer Inputs #

Your current code will crash if the user enters non-integer values (like a string). To make it more robust, you can add an extra except block to catch ValueError:

def in_num():
    a = int(input('Enter a number: '))
    b = int(input('Enter another number: '))
    return a, b

while True:
    try:
        x, y = in_num()
        print(f'The Answer of {x}/{y} is {x/y}')
        break
    except ZeroDivisionError:
        print('Cant divide by zero. Please try again.')
    except ValueError:
        print('Oops! Please enter valid whole numbers. Try again.')

This way, the program will handle both zero divisors and non-integer inputs gracefully, repeating until valid values are provided.

内容的提问来源于stack exchange，提问作者Mtoklitz113