如何不使用正则表达式过滤Python列表中movie后带数字的URL

Absolutely! You don’t need regular expressions to achieve this filtering. Simple string splitting and digit-checking methods work perfectly for your use case.

Approach #

The key idea is to isolate the segment immediately after movie/ and verify if it consists entirely of digits before the next /:

1. For each link, check if it contains the substring movie/ (to skip any unrelated links).
2. Split the link to extract the part right after movie/.
3. Split that extracted part again at the next / to get the segment we need to validate.
4. Use Python’s built-in isdigit() method to check if this segment is all numeric.

Code Implementation #

Using List Comprehension (Python 3.8+) #

This uses the walrus operator (:=) for concise, readable code:

all_links = [
    'afisha.ru/movie/y2010-2019/vybor-afishi/',
    'afisha.ru/movie/257915/',
    'afisha.ru/movie/257574/',
    'afisha.ru/movie/258600/',
    'afisha.ru/movie/257467/',
    'afisha.ru/movie/246562/',
    'afisha.ru/movie/changed_world/'
]

filtered_links = [
    link for link in all_links
    if 'movie/' in link
    and (id_segment := link.split('movie/')[1].split('/')[0]).isdigit()
]

print(filtered_links)

Compatible with Older Python Versions (Pre-3.8) #

If you’re using an older Python version, you can rewrite it without the walrus operator:

all_links = [
    'afisha.ru/movie/y2010-2019/vybor-afishi/',
    'afisha.ru/movie/257915/',
    'afisha.ru/movie/257574/',
    'afisha.ru/movie/258600/',
    'afisha.ru/movie/257467/',
    'afisha.ru/movie/246562/',
    'afisha.ru/movie/changed_world/'
]

filtered_links = []
for link in all_links:
    if 'movie/' not in link:
        continue
    post_movie_part = link.split('movie/')[1]
    id_segment = post_movie_part.split('/')[0]
    if id_segment.isdigit():
        filtered_links.append(link)

print(filtered_links)

Expected Output #

Both code snippets will produce your desired result:

['afisha.ru/movie/257915/', 'afisha.ru/movie/257574/', 'afisha.ru/movie/258600/', 'afisha.ru/movie/257467/', 'afisha.ru/movie/246562/']

Notes #

• This method assumes each link contains movie/ exactly once (as in your example). If you have links with multiple movie/ substrings, you may need to adjust the splitting logic to target the correct occurrence.
• The isdigit() method works here because your valid segments are positive integers. If you ever need to handle negative numbers or decimals, you’d need a slight adjustment, but this fits your use case perfectly.

内容的提问来源于stack exchange，提问作者name_of_user