如何在Python中限制输入尝试次数？测验代码现无限循环求排查

原代码核心问题 #

1. 循环条件完全错误
   原代码用while guess == answer:作为循环条件，这意味着只要用户第一次猜对，就会进入无限循环——因为guess和answer都是函数传入的固定值，循环条件永远为真，会反复打印"正确答案"，无法退出。

2. 尝试次数逻辑混乱

   • attempt初始值设为3，后续却执行attempt +=1，完全搞反了计数方向，应该从0或1开始累加尝试次数，直到达到3次上限。
   • 判断if attempt < 2的逻辑错误，实际应该是当尝试次数未达上限时提示重试。

3. 缺少重试输入逻辑
   函数仅接收外部传入的一次猜测值，没有在循环内重新获取用户的新输入，根本实现不了"多次尝试答题"的需求。

修复后的代码 #

score = 0
print('Hello, and welcome to The Game Show')

def check_questions(question, answer):
    global score
    attempt = 0
    while attempt < 3:
        guess = input(question)
        # 统一格式避免类型/大小写/空格导致的判断错误
        if str(guess).strip().lower() == str(answer).strip().lower():
            print('That is the correct answer.')
            score += 1
            break
        else:
            attempt += 1
            if attempt < 3:
                print('That is not the correct answer. Please try again.')
    if attempt == 3:
        print(f'The correct answer is {answer}.')

check_questions('Where was Hitler born?\n', 'Austria')
check_questions('How many sides does a triangle have?\n', 3)
check_questions('What is h2O?\n', 'water')
check_questions('What was Germany called before WW2?\n', 'Weimar Republic')
check_questions('What is the minimum age required to be the U.S president?\n', 35)

print(f'Thank you for taking the quiz. Your score is {score}.')

修复说明 #

• 将题目传入函数，在函数内部循环获取用户猜测，真正实现多次尝试逻辑。
• 统一将猜测和答案转为字符串并格式化，避免因输入大小写、空格或类型不匹配导致的判断错误。
• 尝试次数从0开始累加，达到3次时退出循环并显示正确答案。
• 猜对后直接break退出循环，避免无效执行。

内容的提问来源于stack exchange，提问作者Mr.Bunberry66