使用Split或Regex提取UFC选手战绩：无法获取平局数的问题

原代码问题分析 #

你的代码无法输出平局数的核心原因有两个：

1. 循环遍历correctRecord的索引，但判断的是原record字符串的字符，两者长度不一致，且correctRecord本身只有两个-，循环中totaldash最多只能到2，永远触发不了第三个分支（平局输出）。
2. 变量复用混乱，用totalwins临时存储所有阶段的数据，逻辑容易出错，且最后一段平局数据没有触发输出的时机。

修复原代码方案 #

调整循环判断对象，并在循环结束后主动输出平局数，同时拆分变量避免混淆：

import re
record = "10-7-3 (W-L-D)" # W = wins, L= Loss, D= Draws
char = "-"
totalwins = ""
totalloss = ""
totaldraws = ""

correctRecord = re.findall('\[[^\]]*\]|\([^\)]*\)|\"[^\"]*\"|\S+', record)[0]

print("The correct record per fighter is:", correctRecord)

totaldash = 0
for i in range(len(correctRecord)):
    if correctRecord[i] == char:
        totaldash += 1
        if totaldash == 1:
            print("The total wins", totalwins)
            totalloss = ""
            totalwins = ""
        elif totaldash == 2:
            print("The total losses ", totalloss)
            totaldraws = ""
            totalloss = ""
    else:
        # 根据当前dash数量分配到对应变量
        if totaldash == 0:
            totalwins += correctRecord[i]
        elif totaldash == 1:
            totalloss += correctRecord[i]
        elif totaldash == 2:
            totaldraws += correctRecord[i]

# 循环结束后输出最后一段平局数据
print("The total draws ", totaldraws)

更简洁的实现方案 #

既然correctRecord是标准的W-L-D格式字符串，直接用split("-")分割即可，无需复杂循环：

import re
record = "10-7-3 (W-L-D)"
# 提取核心胜败平数据
correctRecord = re.findall('\[[^\]]*\]|\([^\)]*\)|\"[^\"]*\"|\S+', record)[0]
# 按"-"分割为三个部分
wins, losses, draws = correctRecord.split("-")

print("The correct record per fighter is:", correctRecord)
print(f"The total wins {wins}")
print(f"The total losses {losses}")
print(f"The total draws {draws}")

关于你尝试的strip方法无效的说明 #

你之前写的correctRecord= str(record.split(separator, 1)[0])存在两个问题：

1. 未定义separator变量，代码会报错；
2. 即使改为split("-", 1)，也只会将字符串分割为["10", "7-3 (W-L-D)"]，只能提取到胜场数，无法获取负场和平局数，因此无法解决问题。

内容的提问来源于stack exchange，提问作者newbie19901