如何在JavaScript中用正则匹配引号内内容并替换（排除外部内容）

你的问题出在正则的贪婪匹配上：.+会尽可能匹配最长的内容，所以会从第一个双引号一直匹配到最后一个双引号，而非每个独立的引号对。

下面是两种可靠的解决方案：

方案1：使用非贪婪匹配正则 #

通过在.+后添加?，将贪婪匹配转为非贪婪匹配，让正则匹配到下一个双引号就停止：

const originalStr = 'The receptionist: "Okay, please wait a moment." After a while, the receptionist smiled and said, "Congratulations, you have obtained a certificate of exemption from the exam for job transfer. With it, you can use it after you reach a certain Level. After completing the job transfer task, you can directly transfer to a specific occupation, a very convenient little gift."';

// 替换引号内的内容，示例：转为大写
const replacedStr = originalStr.replace(/"(.+?)"/g, (fullMatch, innerContent) => {
  return `"${innerContent.toUpperCase()}"`;
});

console.log(replacedStr);

方案2：使用排除型字符集 #

用[^"]匹配除双引号外的任意字符，同样可以精准锁定每个引号对里的内容：

const originalStr = 'The receptionist: "Okay, please wait a moment." After a while, the receptionist smiled and said, "Congratulations, you have obtained a certificate of exemption from the exam for job transfer. With it, you can use it after you reach a certain Level. After completing the job transfer task, you can directly transfer to a specific occupation, a very convenient little gift."';

// 替换引号内的内容，示例：添加自定义前缀
const replacedStr = originalStr.replace(/"([^"]+)"/g, (fullMatch, innerContent) => {
  return `"【处理后：${innerContent}】"`;
});

console.log(replacedStr);

关键说明 #

• (.+?)/([^"]+)：这是捕获组，用于提取引号内的实际内容，你可以在替换函数里对innerContent做任意自定义处理
• /g：全局标志，确保匹配所有符合条件的引号对，而非只匹配第一个

内容的提问来源于stack exchange，提问作者rarksoca