使用while循环与continue语句筛选状态为on的用户信息异常排查

你想用while循环结合continue语句，只输出状态为"on"的用户账号密码，但代码运行后只输出了第一个用户的信息，和预期不符。

原代码 #

name_lst = ["koala", "cat", "fox", "hin"]
pw_lst = ["1111", "2222", "3333", "4444"]
status_lst = ["on", "off", "on", "off"]

i=0
while i < len(name_lst):
if status_lst[i] == "cat":
    continue
print("username: " + name_lst[i])
print("password: " + pw_lst[i])
i = i+1

问题分析 #

1. 判断条件错误：你想跳过状态为"off"的用户，但代码里写的是status_lst[i] == "cat"，完全不匹配状态列表里的值，等于没过滤任何用户。
2. 死循环陷阱：当continue执行时，会直接跳过后续代码回到循环开头，但此时i没有递增，导致程序一直卡在i=1的位置循环，永远处理不了后面的用户。

修正后的代码 #

name_lst = ["koala", "cat", "fox", "hin"]
pw_lst = ["1111", "2222", "3333", "4444"]
status_lst = ["on", "off", "on", "off"]

i=0
while i < len(name_lst):
    if status_lst[i] == "off":
        i += 1  # 先递增索引，再跳过当前循环
        continue
    print("username: " + name_lst[i])
    print("password: " + pw_lst[i])
    i = i+1

运行结果 #

username: koala
password: 1111
username: fox
password: 3333

内容的提问来源于stack exchange，提问作者AA_SS