如何解析指定URL字符串提取数值26并存入变量？

以下是几种主流编程语言的具体实现方案：

Python实现 #

• 正则表达式匹配法

import re

url = "https://20.85.239.243:50000/b1s/v1/Orders(26)"
match_result = re.search(r'\((\d+)\)', url)
if match_result:
    order_id = int(match_result.group(1))
    # 此时order_id变量存储数值26

• 字符串分割法

url = "https://20.85.239.243:50000/b1s/v1/Orders(26)"
order_id = int(url.split('(')[1].split(')')[0])
# 此时order_id变量存储数值26

JavaScript实现 #

• 正则表达式匹配法

const url = "https://20.85.239.243:50000/b1s/v1/Orders(26)";
const matchResult = url.match(/\((\d+)\)/);
if (matchResult) {
    const orderId = parseInt(matchResult[1], 10);
    // 此时orderId变量存储数值26
}

• 字符串截取法

const url = "https://20.85.239.243:50000/b1s/v1/Orders(26)";
const startIndex = url.indexOf('(') + 1;
const endIndex = url.indexOf(')');
const orderId = parseInt(url.slice(startIndex, endIndex), 10);
// 此时orderId变量存储数值26

Java实现 #

• 正则表达式匹配法

import java.util.regex.Matcher;
import java.util.regex.Pattern;

public class UrlParser {
    public static void main(String[] args) {
        String url = "https://20.85.239.243:50000/b1s/v1/Orders(26)";
        Pattern pattern = Pattern.compile("\\((\\d+)\\)");
        Matcher matcher = pattern.matcher(url);
        if (matcher.find()) {
            int orderId = Integer.parseInt(matcher.group(1));
            // 此时orderId变量存储数值26
        }
    }
}

• 字符串分割法

public class UrlParser {
    public static void main(String[] args) {
        String url = "https://20.85.239.243:50000/b1s/v1/Orders(26)";
        String[] splitByLeftParen = url.split("\\(");
        String[] splitByRightParen = splitByLeftParen[1].split("\\)");
        int orderId = Integer.parseInt(splitByRightParen[0]);
        // 此时orderId变量存储数值26
    }
}

内容的提问来源于stack exchange，提问作者Andres Edu