求助：如何用其他方法迭代Excel文件中的列表？附openpyxl代码

你给出的openpyxl代码存在逻辑问题：equipe[cell]里的cell是单元格对象，不能直接作为列表索引，需用cell.value获取单元格内容。以下是修正后的代码，以及其他几种常用的实现方案：

一、修正后的openpyxl实现 #

场景1：将列表写入Excel的A列 #

from openpyxl import load_workbook

wb = load_workbook("italian_team.xlsx")
ws = wb.active

equipe = ["Juventus", "Ac Milan", "Torino", "Pescara", "As Roma", "Genoa", "Napoli"]

# 遍历列表，写入A列对应行（行号从1开始）
for idx, team in enumerate(equipe, start=1):
    ws[f"A{idx}"] = team

wb.save("italian_team.xlsx")

场景2：读取A列内容并与列表匹配 #

from openpyxl import load_workbook

wb = load_workbook("italian_team.xlsx")
ws = wb.active

equipe = ["Juventus", "Ac Milan", "Torino", "Pescara", "As Roma", "Genoa", "Napoli"]

# 遍历A列单元格，过滤空值并匹配列表
for cell in ws["A"]:
    if cell.value and cell.value in equipe:
        print(f"找到匹配球队：{cell.value}")

wb.save("italian_team.xlsx")

二、使用pandas实现（简洁高效，适合批量操作） #

pandas处理表格类数据优势明显，代码更简洁：

import pandas as pd

# 读取Excel文件
df = pd.read_excel("italian_team.xlsx")

equipe = ["Juventus", "Ac Milan", "Torino", "Pescara", "As Roma", "Genoa", "Napoli"]

# 迭代A列内容并匹配列表
for value in df['A'].dropna():
    if value in equipe:
        print(f"匹配到：{value}")

# 将列表写入A列并保存
df['A'] = equipe
df.to_excel("italian_team.xlsx", index=False)

三、使用xlrd/xlwt实现（兼容旧版.xls格式） #

如果需要处理.xls格式文件，可使用这两个库：

import xlrd
import xlwt
from xlutils.copy import copy

# 读取旧版Excel文件
rb = xlrd.open_workbook("italian_team.xls")
wb = copy(rb)
ws = wb.get_sheet(0)

equipe = ["Juventus", "Ac Milan", "Torino", "Pescara", "As Roma", "Genoa", "Napoli"]

# 写入A列（行索引从0开始）
for idx, team in enumerate(equipe):
    ws.write(idx, 0, team)

wb.save("italian_team.xls")

# 读取A列内容并匹配
for row in rb.sheet_by_index(0).col_values(0):
    if row in equipe:
        print(f"找到匹配：{row}")

四、转CSV后用内置csv模块处理 #

若Excel可另存为CSV格式，用内置模块更轻量：

import csv

equipe = ["Juventus", "Ac Milan", "Torino", "Pescara", "As Roma", "Genoa", "Napoli"]

# 读取CSV文件并匹配列表
with open("italian_team.csv", "r", encoding="utf-8") as f:
    reader = csv.reader(f)
    for row in reader:
        if row and row[0] in equipe:
            print(f"匹配成功：{row[0]}")

# 将列表写入CSV文件
with open("italian_team.csv", "w", encoding="utf-8", newline="") as f:
    writer = csv.writer(f)
    for team in equipe:
        writer.writerow([team])

内容的提问来源于stack exchange，提问作者Marouan H