玩家与电脑选择相同时无法打印Draw的Python代码问题

期望在玩家与电脑选择相同选项时打印“Draw”，但代码在电脑选择完成后直接结束，无法正常输出该内容。原代码如下：

rock = '''
    _______
---'   ____)
      (_____)
      (_____)
      (____)
---.__(___)
'''

paper = '''
    _______
---'   ____)____
          ______)
          _______)
         _______)
---.__________)
'''

scissors = '''
    _______
---'   ____)____
          ______)
       __________)
      (____)
---.__(___)
'''

#Write your code below this line 👇

players_choice = input("What do you choose? Type 0 for Rock, 1 for Paper or 2 for Scissors. ")

if players_choice == "0":
  print(rock)
elif players_choice == "1":
   print(paper)
elif players_choice == "2":
  print(scissors)

import random

print("Computer chooses:")

computer_options = [rock, paper, scissors]

computer_choice = random.choice(computer_options)

print(computer_choice)

if computer_choice == players_choice:
  print("Draw")

判断条件的对比对象不匹配：

• players_choice 是用户输入的字符串（"0"/"1"/"2"）
• computer_choice 是随机选中的ASCII图形字符串
  两者类型和内容完全不同，导致if computer_choice == players_choice永远不会触发。

统一对比基准，改用数字索引进行判断，同时保留图形输出：

rock = '''
    _______
---'   ____)
      (_____)
      (_____)
      (____)
---.__(___)
'''

paper = '''
    _______
---'   ____)____
          ______)
          _______)
         _______)
---.__________)
'''

scissors = '''
    _______
---'   ____)____
          ______)
       __________)
      (____)
---.__(___)
'''

#Write your code below this line 👇

players_choice = input("What do you choose? Type 0 for Rock, 1 for Paper or 2 for Scissors. ")
# 将用户输入转为整数，方便后续对比
player_idx = int(players_choice)

# 根据索引打印玩家选择的图形
if player_idx == 0:
  print(rock)
elif player_idx == 1:
   print(paper)
elif player_idx == 2:
  print(scissors)

import random

print("Computer chooses:")

computer_options = [rock, paper, scissors]
# 先随机生成电脑选择的索引
computer_idx = random.randint(0, 2)
computer_choice = computer_options[computer_idx]

print(computer_choice)

# 对比索引判断是否平局
if computer_idx == player_idx:
  print("Draw")

内容的提问来源于stack exchange，提问作者Oran Kelly