Python实现：为多级目录树添加指定层级的Aug 2022子目录

目标目录结构说明 #

原有的目录树如下：

\main_folder\subfolder1_level1
\main_folder\subfolder2_level1
\main_folder\subfolder3_level1
\main_folder\subfolder1_level1\subfolder1_level2
\main_folder\subfolder1_level1\subfolder1_level2\Jul 2022
\main_folder\subfolder1_level1\subfolder1_level2\Jun 2022
\main_folder\subfolder2_level1\Jul 2022
\main_folder\subfolder2_level1\Jun 2022
\main_folder\subfolder3_level1\subfolder3_level2
\main_folder\subfolder3_level1\subfolder3_level2\subfolder3_level3
\main_folder\subfolder3_level1\subfolder3_level2\subfolder3_level3\Jul 2022
\main_folder\subfolder3_level1\subfolder3_level2\subfolder3_level3\Jun 2022

需要新增的Aug 2022目录位置：

• 嵌套在\main_folder\subfolder1_level1\subfolder1_level2下
• 嵌套在\main_folder\subfolder2_level1下
• 嵌套在\main_folder\subfolder3_level1\subfolder3_level2\subfolder3_level3下

Python实现代码 #

方案一：使用现代的pathlib模块（Python 3.4+） #

from pathlib import Path

# 定义所有需要创建的目标路径
target_dirs = [
    Path("main_folder/subfolder1_level1/subfolder1_level2/Aug 2022"),
    Path("main_folder/subfolder2_level1/Aug 2022"),
    Path("main_folder/subfolder3_level1/subfolder3_level2/subfolder3_level3/Aug 2022")
]

for dir_path in target_dirs:
    # parents=True：自动创建不存在的父目录
    # exist_ok=True：目录已存在时不抛出异常
    dir_path.mkdir(parents=True, exist_ok=True)
    print(f"目录已创建或已存在：{dir_path.resolve()}")

方案二：使用兼容范围更广的os模块 #

import os

# 定义所有需要创建的目标路径
target_dirs = [
    "main_folder/subfolder1_level1/subfolder1_level2/Aug 2022",
    "main_folder/subfolder2_level1/Aug 2022",
    "main_folder/subfolder3_level1/subfolder3_level2/subfolder3_level3/Aug 2022"
]

for dir_path in target_dirs:
    # exist_ok=True 需Python 3.2+支持；若用Python 2，可手动判断目录是否存在后再创建
    os.makedirs(dir_path, exist_ok=True)
    print(f"目录已创建或已存在：{os.path.abspath(dir_path)}")

代码说明 #

• 递归创建：通过parents=True（pathlib）或os.makedirs的默认递归特性，自动生成所有不存在的父目录，无需手动逐层创建
• 容错处理：exist_ok=True避免因目标目录已存在而触发报错，让代码更健壮
• 绝对路径输出：方便快速确认目录的实际创建位置

内容的提问来源于stack exchange，提问作者Alan H