基于指定规则筛选Amazon搜索结果的BigQuery SQL实现需求
BigQuery SQL实现Amazon首屏搜索结果筛选逻辑
需求说明
针对每个keyword和report_date,按以下规则筛选首屏(共3条)结果:
- 优先选取最多3条Sponsored(赞助推广)结果
- 若赞助结果不足3条,用Organic(自然搜索)结果补足至3条
- 若无赞助结果,直接取前3条自然结果
示例数据
-- 数据表结构及示例数据 WITH amazon_search_results AS ( SELECT 'test1' AS keyword, '2022-10-10' AS report_date, 1 AS rank_no, 'Sponsored' AS result_type UNION ALL SELECT 'test1' AS keyword, '2022-10-10' AS report_date, 2 AS rank_no, 'Sponsored' AS result_type UNION ALL SELECT 'test1' AS keyword, '2022-10-10' AS report_date, 3 AS rank_no, 'Sponsored' AS result_type UNION ALL SELECT 'test1' AS keyword, '2022-10-10' AS report_date, 4 AS rank_no, 'Sponsored' AS result_type UNION ALL SELECT 'test1' AS keyword, '2022-10-10' AS report_date, 5 AS rank_no, 'Sponsored' AS result_type UNION ALL SELECT 'test1' AS keyword, '2022-10-10' AS report_date, 1 AS rank_no, 'Organic' AS result_type UNION ALL SELECT 'test1' AS keyword, '2022-10-10' AS report_date, 2 AS rank_no, 'Organic' AS result_type UNION ALL SELECT 'test1' AS keyword, '2022-10-10' AS report_date, 3 AS rank_no, 'Organic' AS result_type UNION ALL SELECT 'test2' AS keyword, '2022-10-10' AS report_date, 1 AS rank_no, 'Organic' AS result_type UNION ALL SELECT 'test2' AS keyword, '2022-10-10' AS report_date, 2 AS rank_no, 'Organic' AS result_type UNION ALL SELECT 'test2' AS keyword, '2022-10-10' AS report_date, 3 AS rank_no, 'Organic' AS result_type UNION ALL SELECT 'test2' AS keyword, '2022-10-10' AS report_date, 4 AS rank_no, 'Organic' AS result_type UNION ALL SELECT 'test3' AS keyword, '2022-10-10' AS report_date, 1 AS rank_no, 'Sponsored' AS result_type UNION ALL SELECT 'test3' AS keyword, '2022-10-10' AS report_date, 2 AS rank_no, 'Sponsored' AS result_type UNION ALL SELECT 'test3' AS keyword, '2022-10-10' AS report_date, 1 AS rank_no, 'Organic' AS result_type UNION ALL SELECT 'test3' AS keyword, '2022-10-10' AS report_date, 2 AS rank_no, 'Organic' AS result_type UNION ALL SELECT 'test3' AS keyword, '2022-10-10' AS report_date, 3 AS rank_no, 'Organic' AS result_type )
预期结果
- test1:前3条Sponsored结果
- test2:前3条Organic结果
- test3:前2条Sponsored结果 + 第1条Organic结果
BigQuery SQL解决方案
WITH amazon_search_results AS ( -- 替换为你的实际数据表,或保留示例数据测试 SELECT 'test1' AS keyword, '2022-10-10' AS report_date, 1 AS rank_no, 'Sponsored' AS result_type UNION ALL SELECT 'test1' AS keyword, '2022-10-10' AS report_date, 2 AS rank_no, 'Sponsored' AS result_type UNION ALL SELECT 'test1' AS keyword, '2022-10-10' AS report_date, 3 AS rank_no, 'Sponsored' AS result_type UNION ALL SELECT 'test1' AS keyword, '2022-10-10' AS report_date, 4 AS rank_no, 'Sponsored' AS result_type UNION ALL SELECT 'test1' AS keyword, '2022-10-10' AS report_date, 5 AS rank_no, 'Sponsored' AS result_type UNION ALL SELECT 'test1' AS keyword, '2022-10-10' AS report_date, 1 AS rank_no, 'Organic' AS result_type UNION ALL SELECT 'test1' AS keyword, '2022-10-10' AS report_date, 2 AS rank_no, 'Organic' AS result_type UNION ALL SELECT 'test1' AS keyword, '2022-10-10' AS report_date, 3 AS rank_no, 'Organic' AS result_type UNION ALL SELECT 'test2' AS keyword, '2022-10-10' AS report_date, 1 AS rank_no, 'Organic' AS result_type UNION ALL SELECT 'test2' AS keyword, '2022-10-10' AS report_date, 2 AS rank_no, 'Organic' AS result_type UNION ALL SELECT 'test2' AS keyword, '2022-10-10' AS report_date, 3 AS rank_no, 'Organic' AS result_type UNION ALL SELECT 'test2' AS keyword, '2022-10-10' AS report_date, 4 AS rank_no, 'Organic' AS result_type UNION ALL SELECT 'test3' AS keyword, '2022-10-10' AS report_date, 1 AS rank_no, 'Sponsored' AS result_type UNION ALL SELECT 'test3' AS keyword, '2022-10-10' AS report_date, 2 AS rank_no, 'Sponsored' AS result_type UNION ALL SELECT 'test3' AS keyword, '2022-10-10' AS report_date, 1 AS rank_no, 'Organic' AS result_type UNION ALL SELECT 'test3' AS keyword, '2022-10-10' AS report_date, 2 AS rank_no, 'Organic' AS result_type UNION ALL SELECT 'test3' AS keyword, '2022-10-10' AS report_date, 3 AS rank_no, 'Organic' AS result_type ), ranked_results AS ( SELECT *, -- 按结果类型优先级排序:Sponsored优先,同类型内按rank_no升序 ROW_NUMBER() OVER ( PARTITION BY keyword, report_date ORDER BY CASE result_type WHEN 'Sponsored' THEN 0 ELSE 1 END, rank_no ) AS overall_rank FROM amazon_search_results ) SELECT keyword, report_date, rank_no, result_type FROM ranked_results WHERE overall_rank <= 3 ORDER BY keyword, report_date, overall_rank;
逻辑解释
- 优先级排序:通过
CASE语句给Sponsored结果赋予更高排序优先级(值为0),Organic为1;同类型内按rank_no从小到大排序,确保取到同类结果中的前N条。 - 全局排名:用
ROW_NUMBER()按keyword和report_date分组生成全局overall_rank,该排名会先覆盖Sponsored的前3条,再用Organic补足剩余名额。 - 结果筛选:最后保留
overall_rank <=3的记录,正好满足首屏3条的要求。
搜索方向建议
如果需要扩展逻辑,可以搜索以下关键词:
- BigQuery窗口函数(ROW_NUMBER、PARTITION BY)
- 条件排序(CASE ORDER BY)
- 分组数据优先级筛选
内容的提问来源于stack exchange,提问作者Abhay
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