SQL技术需求:统计员工ID在绩效表两列的出现次数并修正查询语句
员工绩效统计SQL查询优化
表结构
表1 employee:
employee_id, first_name, last_name 2 John Appleseed
表2 performance_review:
employee_id, reviewer_id 2 1 2 3 2 4 1 2 3 2
需求
把first_name和last_name合并成姓名输出,同时统计该员工ID在performance_review表的employee_id列里的出现次数(即该员工作为被评价者的次数),以及同一ID在reviewer_id列里的出现次数(即该员工作为评价者的次数)。
示例输出:
姓名 Employee_id统计次数 Received_review统计次数 ------------------------------------------------------------- John Appleseed 3 2
你当前写的错误SQL(无法正常运行)
SELECT CONCAT([employee_first_name], ' ' , [employee_last_name]) AS employee_full_name, (SELECT COUNT(employee.employee_id) FROM performance_review AS received_review LEFT JOIN performance_review ON employee.employee_id = performance_review.employee_id) AS received_reviews FROM employee
正确的SQL写法
写法一:子查询分别统计(简单直接)
SELECT CONCAT(e.first_name, ' ', e.last_name) AS 姓名, -- 统计该员工作为被评价者的次数 (SELECT COUNT(*) FROM performance_review pr WHERE pr.employee_id = e.employee_id) AS `Employee_id统计次数`, -- 统计该员工作为评价者的次数 (SELECT COUNT(*) FROM performance_review pr WHERE pr.reviewer_id = e.employee_id) AS `Received_review统计次数` FROM employee e;
写法二:先分组统计再关联(适合数据量大的场景)
WITH pr_stats AS ( SELECT employee_id, COUNT(*) AS emp_count, -- 同时统计该员工作为评价者的次数 (SELECT COUNT(*) FROM performance_review pr2 WHERE pr2.reviewer_id = pr1.employee_id) AS rev_count FROM performance_review pr1 GROUP BY employee_id ) SELECT CONCAT(e.first_name, ' ', e.last_name) AS 姓名, -- 用COALESCE处理无数据的情况,返回0而非NULL COALESCE(ps.emp_count, 0) AS `Employee_id统计次数`, COALESCE(ps.rev_count, 0) AS `Received_review统计次数` FROM employee e LEFT JOIN pr_stats ps ON e.employee_id = ps.employee_id;
你的SQL问题点
- 关联逻辑错误:子查询重复引用
performance_review表,但未与主表employee正确关联,导致统计的是全表数据而非当前员工的对应数据。 - 字段名错误:你写的
employee_first_name、employee_last_name不存在,实际表字段为first_name、last_name。 - 统计逻辑混乱:需要分别针对
employee_id和reviewer_id列做独立统计,而非做无效的自连接操作。
内容的提问来源于stack exchange,提问作者Akulav
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