C语言无法打印信息，struct student相关编译错误如何修复？

编译错误信息 #

arrow.c:3:23: 警告：在参数列表内声明的'struct student'在该定义或声明外部不可见
 void printInfo(struct student s1);

                       ^~~~~~~
arrow.c: In function 'main':

arrow.c:13:15: error: type of formal parameter 1 is incomplete
     printInfo(s1);

               ^~

arrow.c: At top level:

arrow.c:18:6: error: conflicting types for 'printInfo'
 void printInfo(struct student s1){

   
   ^~~~~~~~~

arrow.c:3:6: note: previous declaration of 'printInfo' was here
 void printInfo(struct student s1);

原代码 #

void printInfo(struct student s1);

struct student {
    int roll;
    float cgpa;
    char name[100];
};

int main(){
    struct student s1 = {1664, 9.2, "shradha"};
    printInfo(s1);

    return 0;
}

void printInfo(struct student s1){
    printf("student information ; \n");
    printf("student.roll = %d\n", s1.roll);
    printf("student.name = %s\n", s1.name);
    printf("student.cgpa = %f \n ", s1.cgpa);

    s1.roll = 4558;
}

问题原因 #

函数printInfo的声明放在了struct student定义之前，编译器处理函数声明时，还不知道struct student的具体结构，会将其视为不完整类型，导致后续调用函数和定义函数时出现类型不匹配、冲突的错误。

修复方案 #

将struct student的定义移至函数声明之前，确保编译器在处理函数声明时已经知晓结构体的完整类型。

修复后的代码 #

struct student {
    int roll;
    float cgpa;
    char name[100];
};

void printInfo(struct student s1);

int main(){
    struct student s1 = {1664, 9.2, "shradha"};
    printInfo(s1);

    return 0;
}

void printInfo(struct student s1){
    printf("student information ; \n");
    printf("student.roll = %d\n", s1.roll);
    printf("student.name = %s\n", s1.name);
    printf("student.cgpa = %f \n ", s1.cgpa);

    s1.roll = 4558;
}

内容的提问来源于stack exchange，提问作者Ayush Kumar