使用reduce对对象数组中thinking的sum求和报错,如何修复?
修复数组对象属性求和的Reduce错误
你的代码出错的核心原因是没有给reduce设置初始累加值,且累加逻辑错误:
- 第一次迭代时,
a是数组第一个元素(对象类型),b是第二个元素,计算后返回64 + 100 = 164(数值类型) - 第二次迭代时,
a变成了164(数值),此时访问a['thinking'].sum会报错——因为数字没有thinking属性
正确的修复代码
const bests = [ { thinking: { _id: '6347d5b4edc3227f056cbc0c', sum: 64, num: 1 }, listening: { _id: '6347d5b4edc3227f056cbc0d', sum: 129, num: 2 }, speaking: { _id: '6347d5b4edc3227f056cbc0e', sum: 0, num: 2 }, writing: { _id: '6347d5b4edc3227f056cbc0f', sum: 0, num: 0 }, speed: { _id: '6347d5b4edc3227f056cbc10', sum: 187, num: 2 }, overall: { _id: '6347d5b4edc3227f056cbc11', sum: 129, num: 2 } }, { thinking: { _id: '6347e46665609042876fc4a6', sum: 100, num: 1 }, listening: { _id: '6347e46665609042876fc4a7', sum: 100, num: 1 }, speaking: { _id: '6347e46665609042876fc4a8', sum: 100, num: 1 }, writing: { _id: '6347e46665609042876fc4a9', sum: 0, num: 0 }, speed: { _id: '6347e46665609042876fc4aa', sum: 88, num: 1 }, overall: { _id: '6347e46665609042876fc4ab', sum: 100, num: 1 } }, { thinking: { _id: '6347e54f65609042876fc4af', sum: 10, num: 10 }, listening: { _id: '6347e54f65609042876fc4b0', sum: 65, num: 1 }, speaking: { _id: '6347e54f65609042876fc4b1', sum: 0, num: 1 }, writing: { _id: '6347e54f65609042876fc4b2', sum: 0, num: 0 }, speed: { _id: '6347e54f65609042876fc4b3', sum: 95, num: 1 }, overall: { _id: '6347e54f65609042876fc4b4', sum: 65, num: 1 } } ] // 修复后的代码:设置初始值0,每次累加当前元素的thinking.sum const sum = bests.reduce((total, current) => total + current.thinking.sum, 0); console.log('sum::', sum); // 输出 64+100+10 = 174
关键说明
- 给
reduce传入第二个参数0作为初始累加值,确保total从数字开始迭代 - 每次迭代只需要把当前元素的
thinking.sum加到total上,逻辑清晰且不会出现类型错误
内容的提问来源于stack exchange,提问作者Sara Ree
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