URL日期迭代变更的逻辑构建技术问题咨询

Hey there! Let's work through fixing your date iteration and URL generation logic. I see you're aiming to loop through every single day from 2016 to 2020 and plug each date into that Uber Movement URL—solid goal, but your current code has a few kinks we can iron out.

First, let's spot the issues in your current code: #

• Index errors: When you do YYYY[i], i is the year value (like 2016), not a list index. Same goes for MM[j] and DD[k]—you're trying to use the month/day values as indices, which will throw an IndexError right away.
• Invalid dates: Your code loops days 1-31 for every month, but not all months have 31 days (looking at you, February, April, June, etc.). This would generate broken dates like 2016-02-31.
• Loop structure: Your date variable and print(date) line are outside the nested loops, so they'll only run once (and crash before that due to the index issue).

The cleanest solution: Use Python's datetime module #

The datetime library handles all the messy date logic (like leap years, varying month lengths) automatically, so you don't have to reinvent the wheel. Here's a revised version of your code:

from datetime import datetime, timedelta

# Set your date range
start_date = datetime(2016, 1, 1)
end_date = datetime(2020, 12, 31)

current_date = start_date
while current_date <= end_date:
    # Format the date as YYYY-MM-DD (matches the URL's required format)
    date_str = current_date.strftime("%Y-%m-%d")
    # Build the URL with f-strings for readability
    url = f'https://movement.uber.com/explore/atlanta/travel-times/query?si=1074&ti=&ag=taz&dt[tpb]=ALL_DAY&dt[wd;]=1,2,3,4,5,6,7&dt[dr][sd]={date_str}&dt[dr][ed]={date_str}&cd=&sa;=&sdn=&lang=en-US'
    print(url)
    # Jump to the next day
    current_date += timedelta(days=1)

Why this works better: #

• No more invalid dates: datetime automatically skips impossible dates (like February 31) and handles leap years (e.g., 2016's February has 29 days).
• Simpler logic: No nested loops to manage—just a single while loop that increments the day each time.
• Clean formatting: strftime("%Y-%m-%d") ensures months and days are two digits (e.g., 01 instead of 1), which matches the URL's expected date format.

If you prefer to stick with nested loops (for learning purposes): #

If you want to build the date logic manually, you'll need to account for varying month lengths and leap years. Here's how to adjust your code:

# Define the range of years
years = range(2016, 2021)
# Base days per month (index 0 unused, indexes 1-12 = months 1-12)
days_per_month = [0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31]

for year in years:
    # Adjust February days for leap years
    if (year % 4 == 0 and year % 100 != 0) or (year % 400 == 0):
        days_per_month[2] = 29
    else:
        days_per_month[2] = 28
    
    for month in range(1, 13):
        # Get the correct number of days for the current month
        max_days = days_per_month[month]
        for day in range(1, max_days + 1):
            # Format date with leading zeros for months/days
            date_str = f"{year}-{month:02d}-{day:02d}"
            # Build the URL
            url = f'https://movement.uber.com/explore/atlanta/travel-times/query?si=1074&ti=&ag=taz&dt[tpb]=ALL_DAY&dt[wd;]=1,2,3,4,5,6,7&dt[dr][sd]={date_str}&dt[dr][ed]={date_str}&cd=&sa;=&sdn=&lang=en-US'
            print(url)

Key fixes here: #

• We use the year, month, and day variables directly (no need to store them in lists first—your original list creation steps were redundant).
• We adjust February's day count based on whether the year is a leap year.
• We format months and days to two digits with :02d to match the URL's date format.

Either approach will get you the daily URLs you need, but the datetime method is far less error-prone. Give it a try!

内容的提问来源于stack exchange，提问作者Luiz Scheuer