JavaScript：如何从对象内的对象数组中获取含UserId、CategoryId的值

你可以通过遍历specialUser数组，将每个数组元素与外层对象的UserId和CategoryId合并，得到每个元素都包含这两个字段的新数组。以下是具体实现：

JavaScript 示例 #

假设你的原始对象名为data，代码如下：

const data = {
  UserId: '634a336122b4b995d25869d5',      
  CategoryId: '620015b6f61454403daba1b4',
  specialUser: [{
        "startDate": "2022-10-3",
        "endDate": "2022-11-3",
        "priceType": 1,
        "price": 199
    },{
        "startDate": "2022-10-3",
        "endDate": "2022-11-3",
        "priceType": 1,
        "price": 199
    },{
        "startDate": "2022-10-3",
        "endDate": "2022-11-3",
        "priceType": 1,
        "price": 199
    }]
};

// 生成包含目标字段的新数组
const result = data.specialUser.map(item => ({
  ...item, // 保留原元素的所有属性
  UserId: data.UserId,
  CategoryId: data.CategoryId
}));

console.log(result);

执行后，result中的每个元素都会包含startDate、endDate、priceType、price、UserId和CategoryId六个字段。

Python 示例（后端场景可用） #

若使用Python处理，代码如下：

data = {
    'UserId': '634a336122b4b995d25869d5',      
    'CategoryId': '620015b6f61454403daba1b4',
    'specialUser': [
        {"startDate": "2022-10-3", "endDate": "2022-11-3", "priceType": 1, "price": 199},
        {"startDate": "2022-10-3", "endDate": "2022-11-3", "priceType": 1, "price": 199},
        {"startDate": "2022-10-3", "endDate": "2022-11-3", "priceType": 1, "price": 199}
    ]
}

# 处理得到目标列表
result = []
for item in data['specialUser']:
    merged_item = item.copy()
    merged_item['UserId'] = data['UserId']
    merged_item['CategoryId'] = data['CategoryId']
    result.append(merged_item)

print(result)

内容的提问来源于stack exchange，提问作者user20219125